document.write( "Question 1210327: YyThe data represent the scores obtained by 9 applicants in an interview arranged in
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document.write( "ascending order: (3x+2), 22, (4x-2), 23, 25, (5x-4), 29, 29 and (x²-7).
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document.write( "(a) Given that the range is 9, find the
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document.write( "(i) value of .x;
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document.write( "(ii) mean mark of the applicants.
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document.write( "(b) If four of the applicants who obtained the highest score were selected, determine the
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document.write( "pass mark. \n" );
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Algebra.Com's Answer #851893 by mccravyedwin(406)  You can put this solution on YOUR website! \r\n" );
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document.write( "The mean is\r\n" );
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document.write( "The range is\r\n" );
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document.write( "x=6; x=-3.\r\n" );
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document.write( "scores aren't negative, so x = 6\r\n" );
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document.write( "The mean is \r\n" );
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document.write( "So the scores are:\r\n" );
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document.write( "3x+2 = 3(6)+2 = 18+2 = 20 \r\n" );
document.write( "22 = 22 \r\n" );
document.write( "4x-2 = 4(6)-2 = 24-2 = 22\r\n" );
document.write( "23 = 23\r\n" );
document.write( "25 = 25\r\n" );
document.write( "5x-4 = 5(6)-4 = 30-4 = 26\r\n" );
document.write( "29 = 29 \r\n" );
document.write( "29 = 29 \r\n" );
document.write( "x2-7 = (6)2-7 = 36-7 = 29\r\n" );
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document.write( "So they are in non-descending order, not ascending order, as stated.\r\n" );
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document.write( "Since the top 4 scores are 29, 29, 29, 26, all passed, and the applicant \r\n" );
document.write( "with 25 failed, the pass mark had to be 26, assuming it had to be a whole\r\n" );
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document.write( "Edwin \n" );
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