document.write( "Question 1209934: a firm hires 7 technicians and 3 apprentices for total daily wages of 820. if one apprentice is appointed to a technician, the total daily wages become 880. What are thr daily wages for a technician and an apprentice \n" ); document.write( "
Algebra.Com's Answer #851883 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "Here is a quick and easy informal mental solution to the problem.

\n" ); document.write( "The combined wages of 7 technicians and 3 apprentices is 820.
\n" ); document.write( "When one apprentice becomes a technician, the combined wages of 8 technicians and 2 apprentices is 880.
\n" ); document.write( "So when an apprentice becomes a technician, the combined wages go up by 60.

\n" ); document.write( "Have that happen twice more, ending up with 10 technicians and 0 apprentices. The combined wages is now 880 + 60 + 60 = 1000.

\n" ); document.write( "So the wage for each technician is 1000/10 = 100.

\n" ); document.write( "When there were 7 technicians and 3 apprentices, the total wages was 820. The wages for the 7 technicians was 7*100 = 700, so the wages for the 3 apprentices was 820-700 = 120; so the wage for each apprentice is 120/3 = 40.

\n" ); document.write( "Alternatively, once we find that the wages for each technician is 100, we can use the fact that the total wages increase by 60 each time an apprentice becomes a technician to determine that the wage for each apprentice is 100-60 = 40.

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