document.write( "Question 117105: Write the equation of the line that passes through point (0,5) with a slope of 9/7\r
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Algebra.Com's Answer #85181 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "If you want to find the equation of line with a given a slope of \"9%2F7\" which goes through the point (\"0\",\"5\"), you can simply use the point-slope formula to find the equation:\r
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\n" ); document.write( "\n" ); document.write( "---Point-Slope Formula---
\n" ); document.write( "\"y-y%5B1%5D=m%28x-x%5B1%5D%29\" where \"m\" is the slope, and is the given point\r
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\n" ); document.write( "\n" ); document.write( "So lets use the Point-Slope Formula to find the equation of the line\r
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\n" ); document.write( "\n" ); document.write( "\"y-5=%289%2F7%29%28x-0%29\" Plug in \"m=9%2F7\", \"x%5B1%5D=0\", and \"y%5B1%5D=5\" (these values are given)\r
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\n" ); document.write( "\n" ); document.write( "\"y-5=%289%2F7%29x%2B%289%2F7%29%28-0%29\" Distribute \"9%2F7\"\r
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\n" ); document.write( "\n" ); document.write( "\"y-5=%289%2F7%29x%2B0\" Multiply \"9%2F7\" and \"-0\" to get \"0\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=%289%2F7%29x%2B0%2B5\" Add 5 to both sides to isolate y\r
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\n" ); document.write( "\n" ); document.write( "\"y=%289%2F7%29x%2B5\" Combine like terms \"0\" and \"5\" to get \"5\" \r
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\n" ); document.write( "\n" ); document.write( "So the equation of the line with a slope of \"9%2F7\" which goes through the point (\"0\",\"5\") is:\r
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\n" ); document.write( "\n" ); document.write( "\"y=%289%2F7%29x%2B5\" which is now in \"y=mx%2Bb\" form where the slope is \"m=9%2F7\" and the y-intercept is \"b=5\"\r
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\n" ); document.write( "\n" ); document.write( "Notice if we graph the equation \"y=%289%2F7%29x%2B5\" and plot the point (\"0\",\"5\"), we get (note: if you need help with graphing, check out this solver)\r
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\n" ); document.write( "\n" ); document.write( " Graph of \"y=%289%2F7%29x%2B5\" through the point (\"0\",\"5\")\r
\n" ); document.write( "\n" ); document.write( "and we can see that the point lies on the line. Since we know the equation has a slope of \"9%2F7\" and goes through the point (\"0\",\"5\"), this verifies our answer.
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