document.write( "Question 117106: Solve for y.
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Algebra.Com's Answer #85180 by jim_thompson5910(35256) $\"\"$ $\"About$

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Solved by pluggable solver: Converting Linear Equations in Standard form to Slope-Intercept Form (and vice versa)

Convert from standard form (Ax+By = C) to slope-intercept form (y = mx+b)

$\"1x%2B2y=4\"$ Start with the given equation

$\"1x%2B2y-1x=4-1x\"$ Subtract 1x from both sides

$\"2y=-1x%2B4\"$ Simplify

$\"%282y%29%2F%282%29=%28-1x%2B4%29%2F%282%29\"$ Divide both sides by 2 to isolate y

$\"y+=+%28-1x%29%2F%282%29%2B%284%29%2F%282%29\"$ Break up the fraction on the right hand side

$\"y+=+%28-1%2F2%29x%2B2\"$ Reduce and simplify

The original equation $\"1x%2B2y=4\"$ (standard form) is equivalent to $\"y+=+%28-1%2F2%29x%2B2\"$ (slope-intercept form)

The equation $\"y+=+%28-1%2F2%29x%2B2\"$ is in the form $\"y=mx%2Bb\"$ where $\"m=-1%2F2\"$ is the slope and $\"b=2\"$ is the y intercept.

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