document.write( "Question 1167604: Consider \"z%5E5-i=0\"\r
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Algebra.Com's Answer #851719 by ikleyn(52876)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "Consider \"z%5E5-i=0\".\r
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document.write( "Equation  \"z%5E5-i\" = 0  is the same as  \"z%5E5\" = i.\r\n" );
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document.write( "One root is, obviously, z = i,  since  \"i%5E5\" = i.\r\n" );
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document.write( "Let's list all the roots \r\n" );
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document.write( "    \"z%5B1%5D\" = \"cis%28pi%2F%282%2A5%29%29\" = \"cis%28pi%2F10%29\",  \r\n" );
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document.write( "    \"z%5B2%5D\" = \"cis%28pi%2F10+%2B+2pi%2F5%29\" = \"cis%28pi%2F10%2B4pi%2F10%29\" = \"cis%285pi%2F10%29\" = \"cis%28pi%2F2%29\" = i, \r\n" );
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document.write( "              (we just noticed it above !)\r\n" );
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document.write( "    \"z%5B3%5D\" = \"cis%28pi%2F10+%2B+4pi%2F5%29\" = \"cis%28pi%2F10%2B8pi%2F10%29\" = \"cis%289pi%2F10%29\", \r\n" );
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document.write( "    \"z%5B4%5D\" = \"cis%28pi%2F10+%2B+6pi%2F5%29\" = \"cis%28pi%2F10%2B12pi%2F10%29\" = \"cis%2813pi%2F10%29\",\r\n" );
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document.write( "    \"z%5B5%5D\" = \"cis%28pi%2F10+%2B+8pi%2F5%29\" = \"cis%28pi%2F10%2B16pi%2F10%29\" = \"cis%2817pi%2F10%29\".\r\n" );
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document.write( "Notice that  \"z%5B1%5D\"  and  \"z%5B3%5D\"  have opposite real parts and identical imaginary parts.    (*)\r\n" );
document.write( "Similarly,   \"z%5B4%5D\"  and  \"z%5B5%5D\"  have opposite real parts and identical imaginary parts.    (**)\r\n" );
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document.write( "We can write the decomposition of  \"z%5E5-i\"  in the form of the product of linear binomials with the roots\r\n" );
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document.write( "    \"z%5E5-i\" = \"%28z-z%5B1%5D%29%2A%28z-z%5B2%5D%29%2A%28z-z%5B3%5D%29%2A%28z-z%5B4%5D%29%2A%28z-z%5B5%5D%29\" =\r\n" );
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document.write( "                = .    (1)\r\n" );
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document.write( "In this decomposition (1), second and third parentheses will give the product\r\n" );
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document.write( "    \"%28z-cis%28pi%2F10%29%29%2A%28z-cis%289pi%2F10%29%29\" = \"z%5E2+-+%28cis%28pi%2F10%29%2Bcis%289%2F10%29%29+%2B+cis%28pi%2F10%29%2Acis%289pi%2F10%29\".    (2)\r\n" );
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document.write( "Here  \"cis%28pi%2F10%29+%2B+cis%289pi%2F10%29\" = \"2isin%28pi%2F10%29\",  as we noticed in (*),  and  \"cis%28pi%2F10%29%2Acis%289pi%2F10%29\" = \"cis%2810pi%2F10%29\" = \"cis%28pi%29\" = -1.\r\n" );
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document.write( "Therefore, \r\n" );
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document.write( "    \"%28z-cis%28pi%2F10%29%29%2A%28z-cis%289pi%2F10%29%29\" = \"z%5E2+-+2isin%28pi%2F10%29+-1\".\r\n" );
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document.write( "Similarly, in decomposition (1), fourth and fifth parentheses will give the product\r\n" );
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document.write( "    \"%28z-cis%2813pi%2F10%29%29%2A%28z-cis%2817pi%2F10%29%29\" = .    (3)\r\n" );
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document.write( "Here  \"cis%2813pi%2F10%29+%2B+cis%2817pi%2F10%29\" = \"-2isin%283pi%2F10%29\",  as we noticed in (**),  and  \"cis%2813pi%2F10%29%2Acis%2817pi%2F10%29\" = \"cis%2830pi%2F10%29\" = \"cis%283pi%29\" = -1.\r\n" );
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document.write( "Therefore, \r\n" );
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document.write( "    \"%28z-cis%2813pi%2F10%29%29%2A%28z-cis%2817pi%2F10%29%29\" = \"z%5E2+%2B+2isin%283pi%2F10%29+-1\".    (4)\r\n" );
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document.write( "Thus, combining everything in one piece, we get\r\n" );
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document.write( "    If  \"z%5E5-i\" = 0,  then  \"z%5E5-i\" = \"%28z-i%29%2A%28z%5E2+-+2isin%28pi%2F10%29+-1%29%2A%28z%5E2+%2B+2isin%283pi%2F10%29+-1%29\" = 0.\r\n" );
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document.write( "QED.\r\n" );
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document.write( "At this point, the proof is complete.\r\n" );
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\n" ); document.write( "\n" ); document.write( "In her post, @MathLover1 incorrectly read the problem and incorrectly understood
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\n" ); document.write( "\n" ); document.write( "So, her writing in her post is not a proof of the problem' statement
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\n" ); document.write( "\n" ); document.write( "For the peace in your mind, simply ignore that post.\r
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