document.write( "Question 1168059: Individual test scores in a large statistics class are normally distributed with ( m= 84.2 )\r
\n" ); document.write( "\n" ); document.write( " and (s = 12.8 ) Let X represent the test score of a randomly selected student from this\r
\n" ); document.write( "\n" ); document.write( " class. Find the probability P( 80 < X < 86 ). Your solution must include a completely\r
\n" ); document.write( "\n" ); document.write( " labeled sketch of the distribution with the area of interest shaded.
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Algebra.Com's Answer #851677 by CPhill(1987)\"\" \"About 
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Here's how to find the probability $P(80 < X < 86)$, including a completely labeled sketch of the normal distribution:\r
\n" ); document.write( "\n" ); document.write( "**1. Understand the Problem:**\r
\n" ); document.write( "\n" ); document.write( "We have a normally distributed random variable $X$ representing test scores with a mean ($\mu$) of 84.2 and a standard deviation ($\sigma$) of 12.8. We want to find the probability that a randomly selected student's score falls between 80 and 86.\r
\n" ); document.write( "\n" ); document.write( "**2. Convert the Scores to Z-Scores:**\r
\n" ); document.write( "\n" ); document.write( "To find the probability using the standard normal distribution table or calculator, we need to convert the given scores (80 and 86) into z-scores using the formula:\r
\n" ); document.write( "\n" ); document.write( "$z = \frac{X - \mu}{\sigma}$\r
\n" ); document.write( "\n" ); document.write( "* For $X = 80$:
\n" ); document.write( " $z_1 = \frac{80 - 84.2}{12.8} = \frac{-4.2}{12.8} \approx -0.3281$\r
\n" ); document.write( "\n" ); document.write( "* For $X = 86$:
\n" ); document.write( " $z_2 = \frac{86 - 84.2}{12.8} = \frac{1.8}{12.8} \approx 0.1406$\r
\n" ); document.write( "\n" ); document.write( "So, the probability $P(80 < X < 86)$ is equivalent to $P(-0.3281 < Z < 0.1406)$, where $Z$ is the standard normal random variable.\r
\n" ); document.write( "\n" ); document.write( "**3. Find the Probabilities Using the Standard Normal Distribution:**\r
\n" ); document.write( "\n" ); document.write( "We need to find the area under the standard normal curve between $z_1 = -0.3281$ and $z_2 = 0.1406$. We can do this by finding the cumulative probabilities $P(Z < 0.1406)$ and $P(Z < -0.3281)$ and then subtracting the smaller from the larger.\r
\n" ); document.write( "\n" ); document.write( "* $P(Z < 0.1406) \approx 0.5557$ (using a standard normal distribution table or calculator)
\n" ); document.write( "* $P(Z < -0.3281) \approx 0.3713$ (using a standard normal distribution table or calculator)\r
\n" ); document.write( "\n" ); document.write( "Now, subtract the probabilities:\r
\n" ); document.write( "\n" ); document.write( "$P(-0.3281 < Z < 0.1406) = P(Z < 0.1406) - P(Z < -0.3281) \approx 0.5557 - 0.3713 = 0.1844$\r
\n" ); document.write( "\n" ); document.write( "**4. Sketch of the Distribution:**\r
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\n" ); document.write( " Normal Distribution
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\n" ); document.write( " -3s -2s -1s μ +1s +2s +3s Z-scores\r
\n" ); document.write( "\n" ); document.write( " -3(12.8) -2(12.8) -1(12.8) 84.2 +1(12.8) +2(12.8) +3(12.8) Raw Scores
\n" ); document.write( " (-38.4) (-25.6) (-12.8) (12.8) (25.6) (38.4) Deviations from Mean\r
\n" ); document.write( "\n" ); document.write( " 55.8 68.6 71.4 84.2 97.0 109.8 122.6 Approximate Raw Scores\r
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\n" ); document.write( " 80 86
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\n" ); document.write( " z=-0.33 z=0.14\r
\n" ); document.write( "\n" ); document.write( " <----------------------- Shaded Area ----------------------->
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\n" ); document.write( "\n" ); document.write( "**Labeling the Sketch:**\r
\n" ); document.write( "\n" ); document.write( "* **Horizontal Axis:** Labeled as \"Test Scores (X)\" and also showing the corresponding \"Z-scores\" below.
\n" ); document.write( "* **Vertical Axis:** Represents the probability density (not explicitly labeled with values, but the curve shows the shape of the distribution).
\n" ); document.write( "* **Curve:** A bell-shaped curve representing the normal distribution.
\n" ); document.write( "* **Mean (μ):** A vertical line drawn at the mean score of 84.2, labeled with \"μ = 84.2\".
\n" ); document.write( "* **Standard Deviations (s):** Approximate locations of 1, 2, and 3 standard deviations away from the mean are indicated on the raw score axis.
\n" ); document.write( "* **Scores of Interest:** Vertical lines are drawn at the scores 80 and 86 on the horizontal axis.
\n" ); document.write( "* **Corresponding Z-scores:** The z-scores calculated for 80 (-0.33 approximately) and 86 (0.14 approximately) are indicated below the respective raw scores.
\n" ); document.write( "* **Shaded Area:** The area under the curve between the vertical lines at 80 and 86 (or their corresponding z-scores) is shaded. This shaded area represents the probability $P(80 < X < 86)$.\r
\n" ); document.write( "\n" ); document.write( "**Answer:**\r
\n" ); document.write( "\n" ); document.write( "The probability $P(80 < X < 86) \approx \boxed{0.1844}$.
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