document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1168301>Question 1168301</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Fruit & Veg shop sells water in 5-litre bottles.<BR>\n" );
document.write( "2.1 On Wednesday Fruit & Veg shop received $2 530 from selling 5-litre bottles of water at $11.50<BR>\n" );
document.write( "per bottle. How many litres of water were sold on that day? <BR>\n" );
document.write( "2.2 On Thursday, the shop received x $ by selling 5-litre bottles of water at 50 . 11 $  each. In terms<BR>\n" );
document.write( "of ,x how many litres of water were sold on that day? <BR>\n" );
document.write( "2.3 On Friday the shop received $(x  20) by selling 5-litre bottles of water at $9 each. In terms<BR>\n" );
document.write( "of x, how many litres of water were sold on that day? <BR>\n" );
document.write( "2.4 If the number of bottles sold on Thursday equal to the number of bottles sold on Friday, how many<BR>\n" );
document.write( "bottles of water were sold in each of these two days? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #851653 by </B><A HREF=/tutors/aboutme.mpl?userid=CPhill><B>CPhill(1959)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CPhill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=CPhill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=851653\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let's break down each part of the problem:\r<BR>\n" );
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document.write( "**2.1 On Wednesday:**\r<BR>\n" );
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document.write( "* **Price per bottle:** $11.50<BR>\n" );
document.write( "* **Total revenue:** $2530\r<BR>\n" );
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document.write( "To find the number of bottles sold, we divide the total revenue by the price per bottle:\r<BR>\n" );
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document.write( "Number of bottles = Total revenue / Price per bottle<BR>\n" );
document.write( "Number of bottles = $2530 / $11.50 = 220 bottles\r<BR>\n" );
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document.write( "Since each bottle contains 5 litres of water, the total litres of water sold on Wednesday is:\r<BR>\n" );
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document.write( "Total litres = Number of bottles × Litres per bottle<BR>\n" );
document.write( "Total litres = 220 bottles × 5 litres/bottle = 1100 litres\r<BR>\n" );
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document.write( "**Answer to 2.1: 1100 litres of water were sold on Wednesday.**\r<BR>\n" );
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document.write( "**2.2 On Thursday:**\r<BR>\n" );
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document.write( "* **Price per bottle:** $11<BR>\n" );
document.write( "* **Total revenue:** $x\r<BR>\n" );
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document.write( "To find the number of bottles sold, we divide the total revenue by the price per bottle:\r<BR>\n" );
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document.write( "Number of bottles = Total revenue / Price per bottle<BR>\n" );
document.write( "Number of bottles = $x / $11 = \frac{x}{11}$ bottles\r<BR>\n" );
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document.write( "Since each bottle contains 5 litres of water, the total litres of water sold on Thursday is:\r<BR>\n" );
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document.write( "Total litres = Number of bottles × Litres per bottle<BR>\n" );
document.write( "Total litres = $\frac{x}{11}$ bottles × 5 litres/bottle = $\frac{5x}{11}$ litres\r<BR>\n" );
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document.write( "**Answer to 2.2: $\frac{5x}{11}$ litres of water were sold on Thursday.**\r<BR>\n" );
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document.write( "**2.3 On Friday:**\r<BR>\n" );
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document.write( "* **Price per bottle:** $9<BR>\n" );
document.write( "* **Total revenue:** $(x - 20)$\r<BR>\n" );
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document.write( "To find the number of bottles sold, we divide the total revenue by the price per bottle:\r<BR>\n" );
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document.write( "Number of bottles = Total revenue / Price per bottle<BR>\n" );
document.write( "Number of bottles = $\frac{(x - 20)}{9}$ bottles\r<BR>\n" );
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document.write( "Since each bottle contains 5 litres of water, the total litres of water sold on Friday is:\r<BR>\n" );
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document.write( "Total litres = Number of bottles × Litres per bottle<BR>\n" );
document.write( "Total litres = $\frac{(x - 20)}{9}$ bottles × 5 litres/bottle = $\frac{5(x - 20)}{9}$ litres\r<BR>\n" );
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document.write( "**Answer to 2.3: $\frac{5(x - 20)}{9}$ litres of water were sold on Friday.**\r<BR>\n" );
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document.write( "**2.4 If the number of bottles sold on Thursday equals the number of bottles sold on Friday:**\r<BR>\n" );
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document.write( "From our answers to 2.2 and 2.3, the number of bottles sold on Thursday is $\frac{x}{11}$ and the number of bottles sold on Friday is $\frac{x - 20}{9}$. We are given that these are equal:\r<BR>\n" );
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document.write( "$\frac{x}{11} = \frac{x - 20}{9}$\r<BR>\n" );
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document.write( "To solve for x, we can cross-multiply:\r<BR>\n" );
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document.write( "$9x = 11(x - 20)$<BR>\n" );
document.write( "$9x = 11x - 220$\r<BR>\n" );
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document.write( "Now, isolate x:\r<BR>\n" );
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document.write( "$220 = 11x - 9x$<BR>\n" );
document.write( "$220 = 2x$<BR>\n" );
document.write( "$x = \frac{220}{2}$<BR>\n" );
document.write( "$x = 110$\r<BR>\n" );
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document.write( "Now that we have the value of x, we can find the number of bottles sold on Thursday and Friday:\r<BR>\n" );
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document.write( "Number of bottles on Thursday = $\frac{x}{11} = \frac{110}{11} = 10$ bottles\r<BR>\n" );
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document.write( "Number of bottles on Friday = $\frac{x - 20}{9} = \frac{110 - 20}{9} = \frac{90}{9} = 10$ bottles\r<BR>\n" );
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document.write( "**Answer to 2.4: 10 bottles of water were sold on each of these two days.** </SPAN>\n" );
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