document.write( "Question 117094: \"2%2Asqrt%285%29=3%2Asqrt%28x%29\" \n" ); document.write( "
Algebra.Com's Answer #85165 by bucky(2189)\"\" \"About 
You can put this solution on YOUR website!
Given:
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\n" ); document.write( "\"2%2Asqrt%285%29=3%2Asqrt%28x%29\"
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\n" ); document.write( "To solve for x, begin by isolating the term \"sqrt%28x%29\" by dividing both sides of this equation
\n" ); document.write( "by 3 to get:
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\n" ); document.write( "\"%282%2Asqrt%285%29%29%2F3+=+sqrt%28x%29\"
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\n" ); document.write( "To get this into a more standard arrangement, transpose this equation (switch sides) to
\n" ); document.write( "put it into the form:
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\n" ); document.write( "\"sqrt%28x%29+=+%28%282%2Asqrt%285%29%29%2F3%29\"
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\n" ); document.write( "Square both sides and you get:
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\n" ); document.write( "So the answer to this problem is:
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\n" ); document.write( "\"x+=+20%2F9\"
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\n" ); document.write( "Hope this helps you to understand the problem and the process you can follow to get the answer.
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