document.write( "Question 1210203: We choose a positive divisor of 20^{20} at random (with all divisors equally likely to be chosen). What is the probability that we chose a multiple of 5? \n" ); document.write( "
Algebra.Com's Answer #851599 by math_tutor2020(3817)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Refer to the scratch work that tutor greenestamps has written out.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Note that he mentioned \n" ); document.write( "(40+1)(20+1) = 41*21 = 861 \n" ); document.write( "However, it is best to leave it as 41*21 \n" ); document.write( "If you're curious how this formula works, then refer to my response on this page \n" ); document.write( "Additionally you can refer to formula (3) of this page\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "A = number of divisors of 20^20 \n" ); document.write( "B = number of divisors of 20^20 that do not involve 5 (i.e. involve 2's only) \n" ); document.write( "C = number of divisors of 20^20 that have at least one factor of 5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "A = 41*21 \n" ); document.write( "B = 41\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "C = A-B \n" ); document.write( "C = 41*21 - 41 \n" ); document.write( "C = 41*(21 - 1) \n" ); document.write( "C = 41*20\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "D = probability a divisor of 20^20 has at least one factor of 5 \n" ); document.write( "D = C/A \n" ); document.write( "D = (41*20)/(41*21) \n" ); document.write( "D = 20/21 is the final answer in fraction form.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "20/21 = 0.95238 = 95.238% approximately \n" ); document.write( "Round this approximate value however needed. \n" ); document.write( " \n" ); document.write( " |