document.write( "Question 1210203: We choose a positive divisor of 20^{20} at random (with all divisors equally likely to be chosen). What is the probability that we chose a multiple of 5? \n" ); document.write( "
Algebra.Com's Answer #851599 by math_tutor2020(3817)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "Refer to the scratch work that tutor greenestamps has written out.\r
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\n" ); document.write( "\n" ); document.write( "Note that he mentioned
\n" ); document.write( "(40+1)(20+1) = 41*21 = 861
\n" ); document.write( "However, it is best to leave it as 41*21
\n" ); document.write( "If you're curious how this formula works, then refer to my response on this page
\n" ); document.write( "Additionally you can refer to formula (3) of this page\r
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\n" ); document.write( "\n" ); document.write( "A = number of divisors of 20^20
\n" ); document.write( "B = number of divisors of 20^20 that do not involve 5 (i.e. involve 2's only)
\n" ); document.write( "C = number of divisors of 20^20 that have at least one factor of 5\r
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\n" ); document.write( "\n" ); document.write( "A = 41*21
\n" ); document.write( "B = 41\r
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\n" ); document.write( "\n" ); document.write( "C = A-B
\n" ); document.write( "C = 41*21 - 41
\n" ); document.write( "C = 41*(21 - 1)
\n" ); document.write( "C = 41*20\r
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\n" ); document.write( "\n" ); document.write( "D = probability a divisor of 20^20 has at least one factor of 5
\n" ); document.write( "D = C/A
\n" ); document.write( "D = (41*20)/(41*21)
\n" ); document.write( "D = 20/21 is the final answer in fraction form.\r
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\n" ); document.write( "\n" ); document.write( "20/21 = 0.95238 = 95.238% approximately
\n" ); document.write( "Round this approximate value however needed.
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