document.write( "Question 1168437: A ship travels on a N 28o E course. The ship travels until it is due north of a port which is 200 nm due east of the port from which the ship originated.
\n" ); document.write( "How far did the ship travel?
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Algebra.Com's Answer #851569 by CPhill(1959)\"\" \"About 
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Let's solve this problem step-by-step.\r
\n" ); document.write( "\n" ); document.write( "**1. Visualize the Situation**\r
\n" ); document.write( "\n" ); document.write( "* Draw a horizontal line representing the east-west direction.
\n" ); document.write( "* Let P1 be the port from which the ship originated.
\n" ); document.write( "* Let P2 be the port due north of P1's final position.
\n" ); document.write( "* P2 is 200 nautical miles (nm) east of P1.
\n" ); document.write( "* The ship travels on a N 28° E course. This means it travels at an angle of 28° from the north direction towards the east.\r
\n" ); document.write( "\n" ); document.write( "**2. Set Up the Triangle**\r
\n" ); document.write( "\n" ); document.write( "* The ship travels from P1 to a point S.
\n" ); document.write( "* S is due north of P2.
\n" ); document.write( "* We have a right triangle P1SP2.
\n" ); document.write( "* P1P2 = 200 nm (eastward distance)
\n" ); document.write( "* Angle SP1P2 = 90° - 28° = 62°\r
\n" ); document.write( "\n" ); document.write( "**3. Use Trigonometry**\r
\n" ); document.write( "\n" ); document.write( "We need to find the distance P1S, which is the distance the ship traveled.\r
\n" ); document.write( "\n" ); document.write( "* We have angle SP1P2 = 62°, and we know the adjacent side (P1P2 = 200 nm).
\n" ); document.write( "* We need to find the hypotenuse (P1S).
\n" ); document.write( "* We can use the cosine function:\r
\n" ); document.write( "\n" ); document.write( "cos(angle) = adjacent / hypotenuse\r
\n" ); document.write( "\n" ); document.write( "* cos(62°) = P1P2 / P1S
\n" ); document.write( "* cos(62°) = 200 / P1S\r
\n" ); document.write( "\n" ); document.write( "**4. Solve for P1S**\r
\n" ); document.write( "\n" ); document.write( "* P1S = 200 / cos(62°)
\n" ); document.write( "* cos(62°) ≈ 0.4695\r
\n" ); document.write( "\n" ); document.write( "* P1S = 200 / 0.4695
\n" ); document.write( "* P1S ≈ 425.98 nm\r
\n" ); document.write( "\n" ); document.write( "**5. Round to an Appropriate Number of Decimal Places**\r
\n" ); document.write( "\n" ); document.write( "We can round to two decimal places, as it's a practical distance measurement.\r
\n" ); document.write( "\n" ); document.write( "P1S ≈ 426.00 nm\r
\n" ); document.write( "\n" ); document.write( "**Therefore, the ship traveled approximately 426.00 nautical miles.**
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