document.write( "Question 1168437: A ship travels on a N 28o E course. The ship travels until it is due north of a port which is 200 nm due east of the port from which the ship originated.
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document.write( "How far did the ship travel? \n" );
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Algebra.Com's Answer #851569 by CPhill(1959)![]() ![]() You can put this solution on YOUR website! Let's solve this problem step-by-step.\r \n" ); document.write( "\n" ); document.write( "**1. Visualize the Situation**\r \n" ); document.write( "\n" ); document.write( "* Draw a horizontal line representing the east-west direction. \n" ); document.write( "* Let P1 be the port from which the ship originated. \n" ); document.write( "* Let P2 be the port due north of P1's final position. \n" ); document.write( "* P2 is 200 nautical miles (nm) east of P1. \n" ); document.write( "* The ship travels on a N 28° E course. This means it travels at an angle of 28° from the north direction towards the east.\r \n" ); document.write( "\n" ); document.write( "**2. Set Up the Triangle**\r \n" ); document.write( "\n" ); document.write( "* The ship travels from P1 to a point S. \n" ); document.write( "* S is due north of P2. \n" ); document.write( "* We have a right triangle P1SP2. \n" ); document.write( "* P1P2 = 200 nm (eastward distance) \n" ); document.write( "* Angle SP1P2 = 90° - 28° = 62°\r \n" ); document.write( "\n" ); document.write( "**3. Use Trigonometry**\r \n" ); document.write( "\n" ); document.write( "We need to find the distance P1S, which is the distance the ship traveled.\r \n" ); document.write( "\n" ); document.write( "* We have angle SP1P2 = 62°, and we know the adjacent side (P1P2 = 200 nm). \n" ); document.write( "* We need to find the hypotenuse (P1S). \n" ); document.write( "* We can use the cosine function:\r \n" ); document.write( "\n" ); document.write( "cos(angle) = adjacent / hypotenuse\r \n" ); document.write( "\n" ); document.write( "* cos(62°) = P1P2 / P1S \n" ); document.write( "* cos(62°) = 200 / P1S\r \n" ); document.write( "\n" ); document.write( "**4. Solve for P1S**\r \n" ); document.write( "\n" ); document.write( "* P1S = 200 / cos(62°) \n" ); document.write( "* cos(62°) ≈ 0.4695\r \n" ); document.write( "\n" ); document.write( "* P1S = 200 / 0.4695 \n" ); document.write( "* P1S ≈ 425.98 nm\r \n" ); document.write( "\n" ); document.write( "**5. Round to an Appropriate Number of Decimal Places**\r \n" ); document.write( "\n" ); document.write( "We can round to two decimal places, as it's a practical distance measurement.\r \n" ); document.write( "\n" ); document.write( "P1S ≈ 426.00 nm\r \n" ); document.write( "\n" ); document.write( "**Therefore, the ship traveled approximately 426.00 nautical miles.** \n" ); document.write( " \n" ); document.write( " |