document.write( "Question 1168441: Two Coast Guard stations, A and B, are on an east-west line and are 115 km apart. The bearing of a ship from station A is N 18o E, and the bearing of the same ship from station B is N 33o W.\r
\n" ); document.write( "\n" ); document.write( "a) How far is the ship from the east-west line connecting the two Coast Guard stations.
\n" ); document.write( "b) How far is the ship from station A?
\n" ); document.write( "c) How far is the ship from station B?
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Algebra.Com's Answer #851568 by CPhill(1959)\"\" \"About 
You can put this solution on YOUR website!
Let's break down this problem step by step.\r
\n" ); document.write( "\n" ); document.write( "**1. Visualize the Situation**\r
\n" ); document.write( "\n" ); document.write( "* Draw a horizontal line representing the east-west line connecting stations A and B.
\n" ); document.write( "* Place A and B on this line, 115 km apart, with A to the west and B to the east.
\n" ); document.write( "* Draw a line from A in the direction N 18° E.
\n" ); document.write( "* Draw a line from B in the direction N 33° W.
\n" ); document.write( "* The intersection of these two lines is the position of the ship (S).\r
\n" ); document.write( "\n" ); document.write( "**2. Set Up the Triangle**\r
\n" ); document.write( "\n" ); document.write( "* Let S be the position of the ship.
\n" ); document.write( "* We have triangle ABS.
\n" ); document.write( "* AB = 115 km
\n" ); document.write( "* Angle SAB = 90° - 18° = 72°
\n" ); document.write( "* Angle SBA = 90° - 33° = 57°
\n" ); document.write( "* Angle ASB = 180° - (72° + 57°) = 180° - 129° = 51°\r
\n" ); document.write( "\n" ); document.write( "**3. Use the Law of Sines**\r
\n" ); document.write( "\n" ); document.write( "We can use the Law of Sines to find the distances AS and BS:\r
\n" ); document.write( "\n" ); document.write( "* AS / sin(57°) = BS / sin(72°) = AB / sin(51°)\r
\n" ); document.write( "\n" ); document.write( "**b) How far is the ship from station A? (AS)**\r
\n" ); document.write( "\n" ); document.write( "* AS / sin(57°) = 115 / sin(51°)
\n" ); document.write( "* AS = 115 * sin(57°) / sin(51°)
\n" ); document.write( "* AS ≈ 115 * 0.8387 / 0.7771
\n" ); document.write( "* AS ≈ 124.06 km\r
\n" ); document.write( "\n" ); document.write( "**c) How far is the ship from station B? (BS)**\r
\n" ); document.write( "\n" ); document.write( "* BS / sin(72°) = 115 / sin(51°)
\n" ); document.write( "* BS = 115 * sin(72°) / sin(51°)
\n" ); document.write( "* BS ≈ 115 * 0.9511 / 0.7771
\n" ); document.write( "* BS ≈ 140.73 km\r
\n" ); document.write( "\n" ); document.write( "**a) How far is the ship from the east-west line connecting the two Coast Guard stations?**\r
\n" ); document.write( "\n" ); document.write( "Let's call the point where the perpendicular from S to AB meets AB as point P. We need to find the length of SP.\r
\n" ); document.write( "\n" ); document.write( "We can use triangle ASP to find SP.\r
\n" ); document.write( "\n" ); document.write( "* sin(72°) = SP / AS
\n" ); document.write( "* SP = AS * sin(72°)
\n" ); document.write( "* SP ≈ 124.06 * sin(72°)
\n" ); document.write( "* SP ≈ 124.06 * 0.9511
\n" ); document.write( "* SP ≈ 118 km\r
\n" ); document.write( "\n" ); document.write( "Alternatively, we can use triangle BSP.\r
\n" ); document.write( "\n" ); document.write( "* sin(57°) = SP / BS
\n" ); document.write( "* SP = BS * sin(57°)
\n" ); document.write( "* SP ≈ 140.73 * sin(57°)
\n" ); document.write( "* SP ≈ 140.73 * 0.8387
\n" ); document.write( "* SP ≈ 118 km\r
\n" ); document.write( "\n" ); document.write( "**Answers:**\r
\n" ); document.write( "\n" ); document.write( "a) The ship is approximately 118 km from the east-west line connecting the two Coast Guard stations.
\n" ); document.write( "b) The ship is approximately 124.06 km from station A.
\n" ); document.write( "c) The ship is approximately 140.73 km from station B.
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