document.write( "Question 1168530: A regular octagon is emclosed with a circle.it has an extension piece CDFE obtained by extendind F and C to E with BCE is a straight line.AF was the diameter of the circle. FE is a tangent to the circle at F.calclate the size of z(angle FEC) \n" ); document.write( "
Algebra.Com's Answer #851562 by CPhill(1959)![]() ![]() You can put this solution on YOUR website! Let's break down this geometry problem step by step.\r \n" ); document.write( "\n" ); document.write( "**1. Diagram and Definitions**\r \n" ); document.write( "\n" ); document.write( "* We have a regular octagon inscribed in a circle. \n" ); document.write( "* AF is a diameter of the circle. \n" ); document.write( "* FC is extended to E, such that BCE is a straight line. \n" ); document.write( "* FE is a tangent to the circle at F. \n" ); document.write( "* We need to find the measure of angle FEC.\r \n" ); document.write( "\n" ); document.write( "**2. Properties of a Regular Octagon**\r \n" ); document.write( "\n" ); document.write( "* A regular octagon has 8 equal sides and 8 equal interior angles. \n" ); document.write( "* The measure of each interior angle of a regular octagon is: \n" ); document.write( " * (n - 2) * 180° / n = (8 - 2) * 180° / 8 = 6 * 180° / 8 = 135°\r \n" ); document.write( "\n" ); document.write( "**3. Angles in the Diagram**\r \n" ); document.write( "\n" ); document.write( "* Let O be the center of the circle. \n" ); document.write( "* Since the octagon is regular, the central angle subtended by each side is 360° / 8 = 45°. \n" ); document.write( "* Angle AOF is 45 degrees. \n" ); document.write( "* Angle COF is 45 degrees. \n" ); document.write( "* Angle BOC is 45 degrees. \n" ); document.write( "* Since AF is a diameter, angle ACF is 135/2 = 67.5 degrees, because the angle ACF is half the interior angle of the octagon. \n" ); document.write( "* Angle AFC = 135/2 = 67.5 degrees.\r \n" ); document.write( "\n" ); document.write( "**4. Tangent and Diameter Properties**\r \n" ); document.write( "\n" ); document.write( "* Since FE is a tangent to the circle at F, angle AFE = 90°.\r \n" ); document.write( "\n" ); document.write( "**5. Finding Angle CFE**\r \n" ); document.write( "\n" ); document.write( "* We need to find angle CFE. \n" ); document.write( "* Since angle AFC = 67.5 degrees and angle AFE = 90 degrees. \n" ); document.write( "* angle CFE = angle AFE - angle AFC = 90 - 67.5 = 22.5 degrees.\r \n" ); document.write( "\n" ); document.write( "**6. Finding Angle FEC**\r \n" ); document.write( "\n" ); document.write( "* In triangle FEC, we need to find angle FEC. \n" ); document.write( "* Since BCE is a straight line, angle FCB = 180 - 135 = 45 degrees. \n" ); document.write( "* We know angle CFE = 22.5 degrees. \n" ); document.write( "* In triangle FEC, the sum of the angles is 180 degrees. \n" ); document.write( "* angle FEC + angle CFE + angle FCE = 180 degrees. \n" ); document.write( "* angle FEC + 22.5 + 45 = 180 \n" ); document.write( "* angle FEC + 67.5 = 180 \n" ); document.write( "* angle FEC = 180 - 67.5 \n" ); document.write( "* angle FEC = 112.5 degrees.\r \n" ); document.write( "\n" ); document.write( "**Therefore, the size of angle FEC is 112.5 degrees.** \n" ); document.write( " \n" ); document.write( " |