document.write( "Question 1168570: If we roll a die two times, determine whether the following pairs of events are independent or dependent.
\n" ); document.write( "Event A is rolling a 3 on the first die. Event B is getting a sum of more than 6 with the two dice?
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Algebra.Com's Answer #851517 by CPhill(1987)\"\" \"About 
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Let's determine if events A and B are independent or dependent.\r
\n" ); document.write( "\n" ); document.write( "**1. Define the Events**\r
\n" ); document.write( "\n" ); document.write( "* **Event A:** Rolling a 3 on the first die.
\n" ); document.write( "* **Event B:** Getting a sum of more than 6 with the two dice.\r
\n" ); document.write( "\n" ); document.write( "**2. Calculate Probabilities**\r
\n" ); document.write( "\n" ); document.write( "* **P(A):** The probability of rolling a 3 on the first die is 1/6 (since there's one favorable outcome out of six).
\n" ); document.write( "* **P(B):** To find P(B), we need to count the pairs of dice rolls that sum to more than 6.
\n" ); document.write( " * Possible pairs: (1,6), (2,5), (2,6), (3,4), (3,5), (3,6), (4,3), (4,4), (4,5), (4,6), (5,2), (5,3), (5,4), (5,5), (5,6), (6,1), (6,2), (6,3), (6,4), (6,5), (6,6).
\n" ); document.write( " * There are 21 pairs that sum to more than 6.
\n" ); document.write( " * Total possible pairs: 6 * 6 = 36.
\n" ); document.write( " * P(B) = 21/36 = 7/12.
\n" ); document.write( "* **P(A and B):** The probability of both events A and B occurring.
\n" ); document.write( " * We need to count the pairs where the first die is a 3 and the sum is greater than 6.
\n" ); document.write( " * These pairs are: (3,4), (3,5), (3,6).
\n" ); document.write( " * P(A and B) = 3/36 = 1/12.\r
\n" ); document.write( "\n" ); document.write( "**3. Check for Independence**\r
\n" ); document.write( "\n" ); document.write( "* Two events are independent if P(A and B) = P(A) * P(B).
\n" ); document.write( "* Let's check:
\n" ); document.write( " * P(A) * P(B) = (1/6) * (7/12) = 7/72
\n" ); document.write( " * P(A and B) = 1/12 = 6/72\r
\n" ); document.write( "\n" ); document.write( "* Since 7/72 ≠ 6/72, P(A and B) ≠ P(A) * P(B).\r
\n" ); document.write( "\n" ); document.write( "**4. Conclusion**\r
\n" ); document.write( "\n" ); document.write( "* Therefore, events A and B are **dependent**.
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