document.write( "Question 1168931: Find the (standard) equation of the hyperbola whose foci are 𝐹1(-3,0) and 𝐹2(3,0),
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Algebra.Com's Answer #851468 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "given:\r
\n" ); document.write( "\n" ); document.write( "foci are F1(\"-3\",\"0\") and F2(\"3\",\"0\"),
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\n" ); document.write( "\n" ); document.write( "The standard form of a hyperbola with a horizontal transverse axis is \r
\n" ); document.write( "\n" ); document.write( "\"%28x-h%29%5E2%2Fa%5E2-%28y-k%29%5E2%2Fb%5E2=1\"\r
\n" ); document.write( "\n" ); document.write( " where (\"h\",\"k\") is the center of the hyperbola
\n" ); document.write( " \"a\" is the distance from the center to a vertex
\n" ); document.write( " \"b\" is the distance from the center to a co-vertex \r
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\n" ); document.write( "\n" ); document.write( "The center of the hyperbola is the midpoint of the line segment between the foci, which is\r
\n" ); document.write( "\n" ); document.write( "\"h=%28-3%2B3%29%2F2=0\"
\n" ); document.write( "\"k=%280%2B0%29%2F2=0\"\r
\n" ); document.write( "\n" ); document.write( "so, the center of the hyperbola is at (\"0\",\"0\")\r
\n" ); document.write( "\n" ); document.write( "The distance between the foci is \"2a\", so \"2a=6\" =>\"a=3\"\r
\n" ); document.write( "\n" ); document.write( "The distance from each focus to the center is \"c=3\"
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\n" ); document.write( "using \"c%5E2=a%5E2%2Bb%5E2\" find \"b\"\r
\n" ); document.write( "\n" ); document.write( "\"b%5E2=c%5E2-a%5E2\"
\n" ); document.write( "\"b%5E2=3%5E2-3%5E2\"
\n" ); document.write( "\"b%5E2=0\"\r
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\n" ); document.write( "\n" ); document.write( "So, the equation of the hyperbola is: \r
\n" ); document.write( "\n" ); document.write( "\"x%5E2%2F3%5E2-y%5E2%2F0=1\"\r
\n" ); document.write( "\n" ); document.write( "since \"b%5E2=0\", this is \"not\" a valid hyperbola\r
\n" ); document.write( "\n" ); document.write( "The foci and vertices coincide, so the hyperbola degenerates into a line.
\n" ); document.write( "The hyperbola with the given parameters doesn't exist.\r
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