document.write( "Question 1210155: ABCE is a Parallelogram. ADEF is a Rhombus. Find the area of the composite figure.
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Algebra.Com's Answer #851424 by ikleyn(52781)\"\" \"About 
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\n" ); document.write( "\"highlight%28cross%28ABCE%29%29\" ABCF is a Parallelogram. ADEF is a Rhombus. Find the area of the composite figure.
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\n" ); document.write( "\n" ); document.write( "            I edited your post to turn your incorrect writing into a correct problem.\r
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document.write( "In rhombus ADEF, the half of the long diagonal is  \"sqrt%2817%5E2-5%5E2%29\" = \"sqrt%28264%29\" = \"2%2Asqrt%2866%29\" units long.\r\n" );
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document.write( "So, we can find the area of the parallelogram ABCF as  the product of the base FC = 11+5+5 = 21 by the height AG = \"2%2Asqrt%2866%29\".\r\n" );
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document.write( "So, the area of the parallelogram ABCF is  \"21%2A%282%2Asqrt%2866%29%29\" = \"42%2Asqrt%2866%29\".\r\n" );
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document.write( "To it, we should add the area of triangle FDE  \"%281%2F2%29%2A%285%2B5%29%2AGE\" = \"5%2A2%2Asqrt%2866%29\" = \"10%2Asqrt%2866%29\".\r\n" );
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document.write( "Thus, the total combined area is \"42%2Asqrt%2866%29\" + \"10%2Asqrt%2866%29\" = \"52%2Asqrt%2866%29\".\r\n" );
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document.write( "ANSWER.  The total combined area is  \"52%2Asqrt%2866%29\"  square units.\r\n" );
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\n" ); document.write( "\n" ); document.write( "Solved.\r
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\n" ); document.write( "\n" ); document.write( "As simple as a cucumber.\r
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\n" ); document.write( "\n" ); document.write( "Edwin, you do not need to revise your solution - it is correct.\r
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\n" ); document.write( "\n" ); document.write( "The solution by @CPhill is wrong.\r
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