document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=17631>Question 17631</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Determine the perimeter and the area of a rectangle with a length of 12.1 m and a width of 7.3 m. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #8514 by </B><A HREF=/tutors/aboutme.mpl?userid=pwac><B>pwac(253)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=pwac><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=8514\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Perimeter is found by adding together all 4 sides.<BR>\n" );
document.write( "In this case 12.1+12.1+7.3+7.3=perimeter<BR>\n" );
document.write( "or it has an equation:2L x 2W= P. where L is long side,W is width.<BR>\n" );
document.write( "Area is found by multiplying length x width.<BR>\n" );
document.write( "In this case 12.1 x 7.3=area (remember the answer is in square metres)<BR>\n" );
document.write( "Hope this is clear.I'll leave you to do arithmetic.<BR>\n" );
document.write( "Pete </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );