document.write( "Question 1210147: In \triangle ABC, we have AB = AC = 4 and \angle BAC = 45^\circ. If M is the midpoint of BC, then find AM^2. \n" ); document.write( "

Algebra.Com's Answer #851374 by ikleyn(52781) $\"\"$ $\"About$

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\n" ); document.write( "In triangle ABC, we have AB = AC = 4 and angle BAC = 45°. If M is the midpoint of BC, then find AM^2.
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\n" ); document.write( "\n" ); document.write( " This problem is simple, and I will provide a simple solution without referring to \r
\n" ); document.write( "\n" ); document.write( " Apollonius' Theorem, to which average student is unfamiliar 129%.\r
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document.write( "Find BC^2 using the cosine law\r\n" );
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document.write( "    BC^2 =  =  = .    (1)\r\n" );
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document.write( "The area of triangle ABC is\r\n" );
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document.write( "    area =  =  = .    (2)\r\n" );
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document.write( "Another way to calculate the area of triangle ABC is\r\n" );
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document.write( "    area = .   (3)\r\n" );
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document.write( "From (2), we can write\r\n" );
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document.write( "    area^2 =  = 32.\r\n" );
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document.write( "From (3), we can write\r\n" );
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document.write( "    area^2 = .\r\n" );
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document.write( "It gives us this equation\r\n" );
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document.write( "     = 32,\r\n" );
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document.write( "     =  = use (1) =  =  =  =  = .\r\n" );
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document.write( "ANSWER.   = .\r\n" );
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\n" ); document.write( "\n" ); document.write( "Solved adequately in a simple way.\r
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