document.write( "Question 1169896: An article published in the Washington Post claims that 45 percent of all Americans have brown eyes. A random sample of n=76 college students students found 28 who had brown eyes.\r
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document.write( "H0:p=.45
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document.write( "Ha:p≠.45\r
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document.write( "(a) The test statistic is z = \r
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document.write( "(b) P-value = \n" );
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Algebra.Com's Answer #851284 by CPhill(1959)![]() ![]() You can put this solution on YOUR website! Let's break down this hypothesis testing problem step by step.\r \n" ); document.write( "\n" ); document.write( "**Understanding the Problem**\r \n" ); document.write( "\n" ); document.write( "We're conducting a two-tailed z-test for proportions to determine if the proportion of college students with brown eyes is significantly different from the claimed 45% of all Americans.\r \n" ); document.write( "\n" ); document.write( "**Given Information**\r \n" ); document.write( "\n" ); document.write( "* Claimed population proportion (p0) = 0.45 \n" ); document.write( "* Sample size (n) = 76 \n" ); document.write( "* Number of college students with brown eyes (x) = 28 \n" ); document.write( "* Sample proportion (p̂) = x/n = 28/76 ≈ 0.3684 \n" ); document.write( "* Null hypothesis (H0): p = 0.45 \n" ); document.write( "* Alternative hypothesis (Ha): p ≠ 0.45\r \n" ); document.write( "\n" ); document.write( "**(a) Calculating the Test Statistic (z)**\r \n" ); document.write( "\n" ); document.write( "The formula for the z-test statistic for proportions is:\r \n" ); document.write( "\n" ); document.write( "$$z = \frac{\hat{p} - p_0}{\sqrt{\frac{p_0(1 - p_0)}{n}}}$$\r \n" ); document.write( "\n" ); document.write( "Where:\r \n" ); document.write( "\n" ); document.write( "* p̂ is the sample proportion (0.3684) \n" ); document.write( "* p0 is the hypothesized population proportion (0.45) \n" ); document.write( "* n is the sample size (76)\r \n" ); document.write( "\n" ); document.write( "Let's plug in the values:\r \n" ); document.write( "\n" ); document.write( "$$z = \frac{0.3684 - 0.45}{\sqrt{\frac{0.45(1 - 0.45)}{76}}}$$\r \n" ); document.write( "\n" ); document.write( "$$z = \frac{-0.0816}{\sqrt{\frac{0.45(0.55)}{76}}}$$\r \n" ); document.write( "\n" ); document.write( "$$z = \frac{-0.0816}{\sqrt{\frac{0.2475}{76}}}$$\r \n" ); document.write( "\n" ); document.write( "$$z = \frac{-0.0816}{\sqrt{0.0032565789}}$$\r \n" ); document.write( "\n" ); document.write( "$$z = \frac{-0.0816}{0.057066442}$$\r \n" ); document.write( "\n" ); document.write( "$$z \approx -1.4299$$\r \n" ); document.write( "\n" ); document.write( "Therefore, the test statistic is approximately z = -1.43.\r \n" ); document.write( "\n" ); document.write( "**(b) Calculating the p-value**\r \n" ); document.write( "\n" ); document.write( "Since this is a two-tailed test (Ha: p ≠ 0.45), we need to find the area in both tails of the standard normal distribution.\r \n" ); document.write( "\n" ); document.write( "1. **Find the area to the left of z = -1.43:** \n" ); document.write( " * Using a standard normal distribution table or a calculator, the area to the left of z = -1.43 is approximately 0.0764.\r \n" ); document.write( "\n" ); document.write( "2. **Double the area for the two-tailed p-value:** \n" ); document.write( " * Since it's a two-tailed test, we multiply the area by 2: \n" ); document.write( " * p-value = 2 * 0.0764 = 0.1528.\r \n" ); document.write( "\n" ); document.write( "Therefore, the p-value is approximately 0.1528.\r \n" ); document.write( "\n" ); document.write( "**Answers**\r \n" ); document.write( "\n" ); document.write( "(a) The test statistic is z ≈ -1.43.\r \n" ); document.write( "\n" ); document.write( "(b) The p-value ≈ 0.1528. \n" ); document.write( " \n" ); document.write( " |