document.write( "Question 1170336: Find the focus, directrix, and equation of the parabola with vertex at the origin, axis along y-axis; opening upward; and the length of the latus rectum is 12. Sketch the graph. \n" ); document.write( "
Algebra.Com's Answer #851213 by CPhill(1959)\"\" \"About 
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Let's break down this problem step-by-step.\r
\n" ); document.write( "\n" ); document.write( "**1. Equation of the Parabola:**\r
\n" ); document.write( "\n" ); document.write( "* Since the vertex is at the origin (0, 0), the axis is along the y-axis, and the parabola opens upward, the equation of the parabola is of the form:
\n" ); document.write( " $x^2 = 4py$
\n" ); document.write( " where $p > 0$.\r
\n" ); document.write( "\n" ); document.write( "**2. Length of the Latus Rectum:**\r
\n" ); document.write( "\n" ); document.write( "* The length of the latus rectum is given as 12.
\n" ); document.write( "* The length of the latus rectum is also equal to $4p$.
\n" ); document.write( "* Therefore, $4p = 12$.
\n" ); document.write( "* Solving for $p$:
\n" ); document.write( " $p = \frac{12}{4} = 3$\r
\n" ); document.write( "\n" ); document.write( "**3. Equation of the Parabola (Specific):**\r
\n" ); document.write( "\n" ); document.write( "* Substitute $p = 3$ into the equation $x^2 = 4py$:
\n" ); document.write( " $x^2 = 4(3)y$
\n" ); document.write( " $x^2 = 12y$\r
\n" ); document.write( "\n" ); document.write( "**4. Focus:**\r
\n" ); document.write( "\n" ); document.write( "* The focus of the parabola is at (0, p).
\n" ); document.write( "* Since $p = 3$, the focus is at (0, 3).\r
\n" ); document.write( "\n" ); document.write( "**5. Directrix:**\r
\n" ); document.write( "\n" ); document.write( "* The directrix is a horizontal line given by the equation $y = -p$.
\n" ); document.write( "* Since $p = 3$, the directrix is $y = -3$.\r
\n" ); document.write( "\n" ); document.write( "**6. Sketch the Graph:**\r
\n" ); document.write( "\n" ); document.write( "* **Vertex:** (0, 0)
\n" ); document.write( "* **Focus:** (0, 3)
\n" ); document.write( "* **Directrix:** y = -3
\n" ); document.write( "* **Latus Rectum:** The latus rectum passes through the focus and is perpendicular to the axis of symmetry. Its endpoints are at a distance of $2p$ from the focus.
\n" ); document.write( " * Since $2p = 6$, the endpoints of the latus rectum are at (-6, 3) and (6, 3).\r
\n" ); document.write( "\n" ); document.write( "**Graph:**\r
\n" ); document.write( "\n" ); document.write( "```
\n" ); document.write( " ^ y-axis
\n" ); document.write( " |
\n" ); document.write( " |
\n" ); document.write( " 3 | * (0, 3) - Focus
\n" ); document.write( " | / \
\n" ); document.write( " | / \
\n" ); document.write( " |/ \
\n" ); document.write( " 0 +-----------+---> x-axis
\n" ); document.write( " |\ /|
\n" ); document.write( " | \ / |
\n" ); document.write( " | \ / |
\n" ); document.write( " -3 | v - Directrix
\n" ); document.write( " |
\n" ); document.write( "```\r
\n" ); document.write( "\n" ); document.write( "**Summary:**\r
\n" ); document.write( "\n" ); document.write( "* **Equation of the Parabola:** $x^2 = 12y$
\n" ); document.write( "* **Focus:** (0, 3)
\n" ); document.write( "* **Directrix:** $y = -3$
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