document.write( "Question 1170336: Find the focus, directrix, and equation of the parabola with vertex at the origin, axis along y-axis; opening upward; and the length of the latus rectum is 12. Sketch the graph. \n" ); document.write( "
Algebra.Com's Answer #851213 by CPhill(1959)![]() ![]() You can put this solution on YOUR website! Let's break down this problem step-by-step.\r \n" ); document.write( "\n" ); document.write( "**1. Equation of the Parabola:**\r \n" ); document.write( "\n" ); document.write( "* Since the vertex is at the origin (0, 0), the axis is along the y-axis, and the parabola opens upward, the equation of the parabola is of the form: \n" ); document.write( " $x^2 = 4py$ \n" ); document.write( " where $p > 0$.\r \n" ); document.write( "\n" ); document.write( "**2. Length of the Latus Rectum:**\r \n" ); document.write( "\n" ); document.write( "* The length of the latus rectum is given as 12. \n" ); document.write( "* The length of the latus rectum is also equal to $4p$. \n" ); document.write( "* Therefore, $4p = 12$. \n" ); document.write( "* Solving for $p$: \n" ); document.write( " $p = \frac{12}{4} = 3$\r \n" ); document.write( "\n" ); document.write( "**3. Equation of the Parabola (Specific):**\r \n" ); document.write( "\n" ); document.write( "* Substitute $p = 3$ into the equation $x^2 = 4py$: \n" ); document.write( " $x^2 = 4(3)y$ \n" ); document.write( " $x^2 = 12y$\r \n" ); document.write( "\n" ); document.write( "**4. Focus:**\r \n" ); document.write( "\n" ); document.write( "* The focus of the parabola is at (0, p). \n" ); document.write( "* Since $p = 3$, the focus is at (0, 3).\r \n" ); document.write( "\n" ); document.write( "**5. Directrix:**\r \n" ); document.write( "\n" ); document.write( "* The directrix is a horizontal line given by the equation $y = -p$. \n" ); document.write( "* Since $p = 3$, the directrix is $y = -3$.\r \n" ); document.write( "\n" ); document.write( "**6. Sketch the Graph:**\r \n" ); document.write( "\n" ); document.write( "* **Vertex:** (0, 0) \n" ); document.write( "* **Focus:** (0, 3) \n" ); document.write( "* **Directrix:** y = -3 \n" ); document.write( "* **Latus Rectum:** The latus rectum passes through the focus and is perpendicular to the axis of symmetry. Its endpoints are at a distance of $2p$ from the focus. \n" ); document.write( " * Since $2p = 6$, the endpoints of the latus rectum are at (-6, 3) and (6, 3).\r \n" ); document.write( "\n" ); document.write( "**Graph:**\r \n" ); document.write( "\n" ); document.write( "``` \n" ); document.write( " ^ y-axis \n" ); document.write( " | \n" ); document.write( " | \n" ); document.write( " 3 | * (0, 3) - Focus \n" ); document.write( " | / \ \n" ); document.write( " | / \ \n" ); document.write( " |/ \ \n" ); document.write( " 0 +-----------+---> x-axis \n" ); document.write( " |\ /| \n" ); document.write( " | \ / | \n" ); document.write( " | \ / | \n" ); document.write( " -3 | v - Directrix \n" ); document.write( " | \n" ); document.write( "```\r \n" ); document.write( "\n" ); document.write( "**Summary:**\r \n" ); document.write( "\n" ); document.write( "* **Equation of the Parabola:** $x^2 = 12y$ \n" ); document.write( "* **Focus:** (0, 3) \n" ); document.write( "* **Directrix:** $y = -3$ \n" ); document.write( " \n" ); document.write( " |