document.write( "Question 1170393: A researcher suspects that the actual prevalence among children and adolescents is higher than the previously reported prevalence of GAD among children and adolescents. The previously reported prevalence is 3.9% and the researcher conducts a study to test the accuracy of the previous reported prevalence of GAD by recruiting 98 children and adolescents from various pediatrician's offices and tests them for GAD using the DSM-5. The researcher determines that the prevalence of GAD is 6.1%. What should the researchers conclusion be for 5% significance level? \n" ); document.write( "
Algebra.Com's Answer #851210 by CPhill(1987)\"\" \"About 
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Here's how to approach this hypothesis test:\r
\n" ); document.write( "\n" ); document.write( "**1. Define the Hypotheses:**\r
\n" ); document.write( "\n" ); document.write( "* **Null Hypothesis (H0):** The actual prevalence of GAD among children and adolescents is 3.9% (p = 0.039).
\n" ); document.write( "* **Alternative Hypothesis (H1):** The actual prevalence of GAD among children and adolescents is higher than 3.9% (p > 0.039).\r
\n" ); document.write( "\n" ); document.write( "**2. Set the Significance Level:**\r
\n" ); document.write( "\n" ); document.write( "* α = 0.05 (5% significance level)\r
\n" ); document.write( "\n" ); document.write( "**3. Calculate the Sample Proportion:**\r
\n" ); document.write( "\n" ); document.write( "* Sample size (n) = 98
\n" ); document.write( "* Number of children with GAD = 98 * 0.061 = 5.978. Since you cant have a fraction of a child, we will round to 6.
\n" ); document.write( "* Sample proportion (p̂) = 6 / 98 ≈ 0.0612\r
\n" ); document.write( "\n" ); document.write( "**4. Perform the Hypothesis Test (One-Proportion Z-Test):**\r
\n" ); document.write( "\n" ); document.write( "* We'll use a one-proportion z-test because we're dealing with proportions.
\n" ); document.write( "* The test statistic (z) is calculated as:\r
\n" ); document.write( "\n" ); document.write( " $z = \frac{\hat{p} - p}{\sqrt{\frac{p(1-p)}{n}}}$\r
\n" ); document.write( "\n" ); document.write( " Where:
\n" ); document.write( " * p̂ = sample proportion (0.0612)
\n" ); document.write( " * p = population proportion (0.039)
\n" ); document.write( " * n = sample size (98)\r
\n" ); document.write( "\n" ); document.write( "* Now we plug in the values:\r
\n" ); document.write( "\n" ); document.write( " $z = \frac{0.0612 - 0.039}{\sqrt{\frac{0.039(1-0.039)}{98}}}$\r
\n" ); document.write( "\n" ); document.write( " $z = \frac{0.0222}{\sqrt{\frac{0.039(0.961)}{98}}}$\r
\n" ); document.write( "\n" ); document.write( " $z = \frac{0.0222}{\sqrt{\frac{0.03748}{98}}}$\r
\n" ); document.write( "\n" ); document.write( " $z = \frac{0.0222}{\sqrt{0.0003824}}$\r
\n" ); document.write( "\n" ); document.write( " $z = \frac{0.0222}{0.01955}$\r
\n" ); document.write( "\n" ); document.write( " $z ≈ 1.135$\r
\n" ); document.write( "\n" ); document.write( "**5. Determine the Critical Value or P-value:**\r
\n" ); document.write( "\n" ); document.write( "* Since this is a right-tailed test (H1: p > 0.039), we need to find the critical z-value for α = 0.05.
\n" ); document.write( "* Using a standard normal distribution table or calculator, the critical z-value is approximately 1.645.
\n" ); document.write( "* Alternativly we can calculate the p value.
\n" ); document.write( "* Using a z value of 1.135, and a right tailed test, the p value is .128.\r
\n" ); document.write( "\n" ); document.write( "**6. Make a Decision:**\r
\n" ); document.write( "\n" ); document.write( "* **Critical Value Method:**
\n" ); document.write( " * Our calculated z-value (1.135) is less than the critical z-value (1.645).
\n" ); document.write( " * Therefore, we fail to reject the null hypothesis.\r
\n" ); document.write( "\n" ); document.write( "* **P-value method:**
\n" ); document.write( " * The p value of .128 is larger than the significance level of .05.
\n" ); document.write( " * Therefore, we fail to reject the null hypothesis.\r
\n" ); document.write( "\n" ); document.write( "**7. Draw a Conclusion:**\r
\n" ); document.write( "\n" ); document.write( "* At the 5% significance level, there is not enough evidence to support the researcher's claim that the actual prevalence of GAD among children and adolescents is higher than 3.9%.
\n" ); document.write( "* The researcher should conclude that the difference between the sample proportion and the previously reported proportion is not statistically significant.\r
\n" ); document.write( "\n" ); document.write( "**In summary:** The researcher does not have sufficient evidence to reject the previously reported prevalence.
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