document.write( "Question 1209946: 1. The sum of 4 integers is 24 and their product is 945. What are those integers?\r
\n" ); document.write( "\n" ); document.write( "2. Find the sum of all natural numbers between 500 and 1000 which are divisible by 13.\r
\n" ); document.write( "\n" ); document.write( "3. If the sum of three consecutive numbers of an AP is 15 and the sum of the squares of its 1st and 3rd terms is 58, find the numbers.
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Algebra.Com's Answer #851195 by greenestamps(13203)\"\" \"About 
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\n" ); document.write( "1. The sum of 4 integers is 24 and their product is 945. What are those integers?

\n" ); document.write( "Find that the prime factorization of 945 is 3*3*3*5*7. That's 5 factors; we need to combine 2 of them to express 945 as the product of 4 factors. Play with the numbers to find 3*5*7*9 = 945 and 3+5+7+9 = 24.

\n" ); document.write( "ANSWER: 3, 5, 7, and 9

\n" ); document.write( "2. Find the sum of all natural numbers between 500 and 1000 which are divisible by 13.

\n" ); document.write( "500/13 = 38.46... so 13*39 = 507 is the first number we are looking for.
\n" ); document.write( "1000/13 = 76.93... so 13*76 = 988 is the last one.

\n" ); document.write( "The sum we are to find is 13*(39+40+41+...+75+76)

\n" ); document.write( "The sum of an arithmetic sequence is (number of terms)*(average of terms).

\n" ); document.write( "Number of terms: (76-39)+1 = 38
\n" ); document.write( "Average of terms = average of first and last: (39+76)/2 = 115/2

\n" ); document.write( "The sum of the terms is 13(38*115/2) = 13*19*115 = 28405

\n" ); document.write( "ANSWER: 28405

\n" ); document.write( "3. If the sum of three consecutive numbers of an AP is 15 and the sum of the squares of its 1st and 3rd terms is 58, find the numbers.

\n" ); document.write( "Since the sum of 3 consecutive terms of an AP is 15, the middle number is 5. Do some quick calculations to find the other two numbers.

\n" ); document.write( "4 and 6? 4^2+6^2 = 16+36 = 52, not 58

\n" ); document.write( "3 and 7? 3^2+7^2 = 9+49 = 58. YES!

\n" ); document.write( "ANSWER: 3, 5, and 7

\n" ); document.write( "NOTE: Unlike the first problem, this problem has a relatively easy formal algebraic solution.

\n" ); document.write( "Again starting from the fact that the middle number is 5, let the other two numbers be 5-x and 5+x. The sum of the squares of those two numbers is 58:

\n" ); document.write( "\"%285-x%29%5E2%2B%285%2Bx%29%5E2=58\"
\n" ); document.write( "\"25-10x%2Bx%5E2%2B25%2B10x%2Bx%5E2=58\"
\n" ); document.write( "\"50%2B2x%5E2=58\"
\n" ); document.write( "\"2x%5E2=8\"
\n" ); document.write( "\"x%5E2=4\"
\n" ); document.write( "\"x=2\"

\n" ); document.write( "And then the numbers are 5-x = 5-2 = 3, 5, and 5+x = 5+2 = 7.

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