document.write( "Question 1209946: 1. The sum of 4 integers is 24 and their product is 945. What are those integers?\r
\n" ); document.write( "\n" ); document.write( "2. Find the sum of all natural numbers between 500 and 1000 which are divisible by 13.\r
\n" ); document.write( "\n" ); document.write( "3. If the sum of three consecutive numbers of an AP is 15 and the sum of the squares of its 1st and 3rd terms is 58, find the numbers.
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Algebra.Com's Answer #851182 by CPhill(1959)\"\" \"About 
You can put this solution on YOUR website!
Let's solve each problem step-by-step.\r
\n" ); document.write( "\n" ); document.write( "**1. Finding the 4 Integers**\r
\n" ); document.write( "\n" ); document.write( "* Let the 4 integers be $a, b, c, d$.
\n" ); document.write( "* We are given:
\n" ); document.write( " * $a + b + c + d = 24$
\n" ); document.write( " * $a \cdot b \cdot c \cdot d = 945$
\n" ); document.write( "* First, find the prime factorization of 945:
\n" ); document.write( " * $945 = 3^3 \cdot 5 \cdot 7 = 3 \cdot 3 \cdot 3 \cdot 5 \cdot 7$
\n" ); document.write( "* We need to find 4 integers that multiply to 945 and add to 24.
\n" ); document.write( "* Let's try different combinations:
\n" ); document.write( " * If we take 3, 5, 7, the remaining factor is 9. 3+5+7+9 = 24. 3*5*7*9 = 945.
\n" ); document.write( "* Thus, the integers are 3, 5, 7, and 9.\r
\n" ); document.write( "\n" ); document.write( "**2. Sum of Natural Numbers Divisible by 13**\r
\n" ); document.write( "\n" ); document.write( "* We need to find the sum of natural numbers between 500 and 1000 that are divisible by 13.
\n" ); document.write( "* The first number divisible by 13 greater than 500 is:
\n" ); document.write( " * $500 / 13 \approx 38.46$, so the first number is $39 \cdot 13 = 507$.
\n" ); document.write( "* The last number divisible by 13 less than 1000 is:
\n" ); document.write( " * $1000 / 13 \approx 76.92$, so the last number is $76 \cdot 13 = 988$.
\n" ); document.write( "* We have an arithmetic progression (AP) with:
\n" ); document.write( " * First term ($a_1$) = 507
\n" ); document.write( " * Common difference ($d$) = 13
\n" ); document.write( " * Last term ($a_n$) = 988
\n" ); document.write( "* To find the number of terms ($n$):
\n" ); document.write( " * $a_n = a_1 + (n - 1)d$
\n" ); document.write( " * $988 = 507 + (n - 1)13$
\n" ); document.write( " * $481 = (n - 1)13$
\n" ); document.write( " * $n - 1 = 481 / 13 = 37$
\n" ); document.write( " * $n = 38$
\n" ); document.write( "* To find the sum of the AP ($S_n$):
\n" ); document.write( " * $S_n = \frac{n}{2}(a_1 + a_n)$
\n" ); document.write( " * $S_{38} = \frac{38}{2}(507 + 988)$
\n" ); document.write( " * $S_{38} = 19(1495) = 28405$\r
\n" ); document.write( "\n" ); document.write( "**3. Consecutive Numbers in AP**\r
\n" ); document.write( "\n" ); document.write( "* Let the three consecutive numbers in AP be $a - d$, $a$, and $a + d$.
\n" ); document.write( "* We are given:
\n" ); document.write( " * $(a - d) + a + (a + d) = 15$
\n" ); document.write( " * $(a - d)^2 + (a + d)^2 = 58$
\n" ); document.write( "* From the first equation:
\n" ); document.write( " * $3a = 15$
\n" ); document.write( " * $a = 5$
\n" ); document.write( "* Substitute $a = 5$ into the second equation:
\n" ); document.write( " * $(5 - d)^2 + (5 + d)^2 = 58$
\n" ); document.write( " * $25 - 10d + d^2 + 25 + 10d + d^2 = 58$
\n" ); document.write( " * $50 + 2d^2 = 58$
\n" ); document.write( " * $2d^2 = 8$
\n" ); document.write( " * $d^2 = 4$
\n" ); document.write( " * $d = \pm 2$
\n" ); document.write( "* If $d = 2$, the numbers are $5 - 2$, $5$, $5 + 2$, which are 3, 5, 7.
\n" ); document.write( "* If $d = -2$, the numbers are $5 - (-2)$, $5$, $5 + (-2)$, which are 7, 5, 3.\r
\n" ); document.write( "\n" ); document.write( "**Summary**\r
\n" ); document.write( "\n" ); document.write( "1. The integers are 3, 5, 7, and 9.
\n" ); document.write( "2. The sum is 28405.
\n" ); document.write( "3. The numbers are 3, 5, 7.
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