document.write( "Question 1209946: 1. The sum of 4 integers is 24 and their product is 945. What are those integers?\r
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document.write( "2. Find the sum of all natural numbers between 500 and 1000 which are divisible by 13.\r
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document.write( "3. If the sum of three consecutive numbers of an AP is 15 and the sum of the squares of its 1st and 3rd terms is 58, find the numbers. \n" );
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Algebra.Com's Answer #851182 by CPhill(1959)![]() ![]() You can put this solution on YOUR website! Let's solve each problem step-by-step.\r \n" ); document.write( "\n" ); document.write( "**1. Finding the 4 Integers**\r \n" ); document.write( "\n" ); document.write( "* Let the 4 integers be $a, b, c, d$. \n" ); document.write( "* We are given: \n" ); document.write( " * $a + b + c + d = 24$ \n" ); document.write( " * $a \cdot b \cdot c \cdot d = 945$ \n" ); document.write( "* First, find the prime factorization of 945: \n" ); document.write( " * $945 = 3^3 \cdot 5 \cdot 7 = 3 \cdot 3 \cdot 3 \cdot 5 \cdot 7$ \n" ); document.write( "* We need to find 4 integers that multiply to 945 and add to 24. \n" ); document.write( "* Let's try different combinations: \n" ); document.write( " * If we take 3, 5, 7, the remaining factor is 9. 3+5+7+9 = 24. 3*5*7*9 = 945. \n" ); document.write( "* Thus, the integers are 3, 5, 7, and 9.\r \n" ); document.write( "\n" ); document.write( "**2. Sum of Natural Numbers Divisible by 13**\r \n" ); document.write( "\n" ); document.write( "* We need to find the sum of natural numbers between 500 and 1000 that are divisible by 13. \n" ); document.write( "* The first number divisible by 13 greater than 500 is: \n" ); document.write( " * $500 / 13 \approx 38.46$, so the first number is $39 \cdot 13 = 507$. \n" ); document.write( "* The last number divisible by 13 less than 1000 is: \n" ); document.write( " * $1000 / 13 \approx 76.92$, so the last number is $76 \cdot 13 = 988$. \n" ); document.write( "* We have an arithmetic progression (AP) with: \n" ); document.write( " * First term ($a_1$) = 507 \n" ); document.write( " * Common difference ($d$) = 13 \n" ); document.write( " * Last term ($a_n$) = 988 \n" ); document.write( "* To find the number of terms ($n$): \n" ); document.write( " * $a_n = a_1 + (n - 1)d$ \n" ); document.write( " * $988 = 507 + (n - 1)13$ \n" ); document.write( " * $481 = (n - 1)13$ \n" ); document.write( " * $n - 1 = 481 / 13 = 37$ \n" ); document.write( " * $n = 38$ \n" ); document.write( "* To find the sum of the AP ($S_n$): \n" ); document.write( " * $S_n = \frac{n}{2}(a_1 + a_n)$ \n" ); document.write( " * $S_{38} = \frac{38}{2}(507 + 988)$ \n" ); document.write( " * $S_{38} = 19(1495) = 28405$\r \n" ); document.write( "\n" ); document.write( "**3. Consecutive Numbers in AP**\r \n" ); document.write( "\n" ); document.write( "* Let the three consecutive numbers in AP be $a - d$, $a$, and $a + d$. \n" ); document.write( "* We are given: \n" ); document.write( " * $(a - d) + a + (a + d) = 15$ \n" ); document.write( " * $(a - d)^2 + (a + d)^2 = 58$ \n" ); document.write( "* From the first equation: \n" ); document.write( " * $3a = 15$ \n" ); document.write( " * $a = 5$ \n" ); document.write( "* Substitute $a = 5$ into the second equation: \n" ); document.write( " * $(5 - d)^2 + (5 + d)^2 = 58$ \n" ); document.write( " * $25 - 10d + d^2 + 25 + 10d + d^2 = 58$ \n" ); document.write( " * $50 + 2d^2 = 58$ \n" ); document.write( " * $2d^2 = 8$ \n" ); document.write( " * $d^2 = 4$ \n" ); document.write( " * $d = \pm 2$ \n" ); document.write( "* If $d = 2$, the numbers are $5 - 2$, $5$, $5 + 2$, which are 3, 5, 7. \n" ); document.write( "* If $d = -2$, the numbers are $5 - (-2)$, $5$, $5 + (-2)$, which are 7, 5, 3.\r \n" ); document.write( "\n" ); document.write( "**Summary**\r \n" ); document.write( "\n" ); document.write( "1. The integers are 3, 5, 7, and 9. \n" ); document.write( "2. The sum is 28405. \n" ); document.write( "3. The numbers are 3, 5, 7. \n" ); document.write( " \n" ); document.write( " |