document.write( "Question 1209947: You intend to estimate a population mean with a confidence interval. You believe the population to have a normal distribution. Your sample size is 4.\r
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document.write( "While it is an uncommon confidence level, find the critical value that corresponds to a confidence level of 80.5%.
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document.write( "(Report answer accurate to three decimal places with appropriate rounding.)\r
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document.write( "ta/2 +/- = \n" );
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Algebra.Com's Answer #851181 by CPhill(1959)![]() ![]() You can put this solution on YOUR website! Let $n$ be the sample size, which is $n=4$. \n" ); document.write( "The confidence level is 80.5%, or 0.805. \n" ); document.write( "The significance level $\alpha$ is $1 - 0.805 = 0.195$. \n" ); document.write( "The area in each tail is $\alpha/2 = 0.195/2 = 0.0975$.\r \n" ); document.write( "\n" ); document.write( "Since the population is normally distributed and the sample size is small ($n=4$), we need to use a t-distribution with $n-1 = 4-1 = 3$ degrees of freedom.\r \n" ); document.write( "\n" ); document.write( "We need to find the t-value $t_{\alpha/2}$ such that the area to the right of $t_{\alpha/2}$ is 0.0975.\r \n" ); document.write( "\n" ); document.write( "We can use a t-table or a calculator to find this value. \n" ); document.write( "Using a t-table or calculator, we find that the t-value corresponding to an area of 0.0975 in the right tail with 3 degrees of freedom is approximately 1.589.\r \n" ); document.write( "\n" ); document.write( "Therefore, $t_{\alpha/2} \approx 1.589$.\r \n" ); document.write( "\n" ); document.write( "The critical value that corresponds to a confidence level of 80.5% is approximately 1.589.\r \n" ); document.write( "\n" ); document.write( "Final Answer: The final answer is $\boxed{1.589}$ \n" ); document.write( " \n" ); document.write( " |