document.write( "Question 1170505: A machine fills pop bottles with a standard deviation of 25 mL no matter what the setting is for the mean. At how many mililiters should the mean be set, so that 90% of the bottles will contain at least 500 mL? \n" ); document.write( "
Algebra.Com's Answer #851167 by CPhill(1959)![]() ![]() You can put this solution on YOUR website! Let X be the amount of liquid filled in the pop bottles. We are given:\r \n" ); document.write( "\n" ); document.write( "* Standard deviation (σ) = 25 mL \n" ); document.write( "* We want 90% of the bottles to contain at least 500 mL, which means P(X ≥ 500) = 0.90.\r \n" ); document.write( "\n" ); document.write( "We want to find the mean (μ) such that this condition is satisfied.\r \n" ); document.write( "\n" ); document.write( "**1. Convert to Standard Normal Distribution**\r \n" ); document.write( "\n" ); document.write( "We can standardize the random variable X using the formula:\r \n" ); document.write( "\n" ); document.write( "Z = (X - μ) / σ\r \n" ); document.write( "\n" ); document.write( "where Z follows a standard normal distribution (mean 0, standard deviation 1).\r \n" ); document.write( "\n" ); document.write( "We want P(X ≥ 500) = 0.90. Let's rewrite this in terms of Z:\r \n" ); document.write( "\n" ); document.write( "P((X - μ) / σ ≥ (500 - μ) / 25) = 0.90 \n" ); document.write( "P(Z ≥ (500 - μ) / 25) = 0.90\r \n" ); document.write( "\n" ); document.write( "**2. Find the Z-score**\r \n" ); document.write( "\n" ); document.write( "We need to find the z-score such that the area to the right of it is 0.90. This means the area to the left of it is 1 - 0.90 = 0.10.\r \n" ); document.write( "\n" ); document.write( "Using a standard normal distribution table or a calculator, we find the z-score corresponding to a cumulative probability of 0.10. This z-score is approximately -1.28.\r \n" ); document.write( "\n" ); document.write( "So, (500 - μ) / 25 = -1.28.\r \n" ); document.write( "\n" ); document.write( "**3. Solve for μ**\r \n" ); document.write( "\n" ); document.write( "Now, we solve for μ:\r \n" ); document.write( "\n" ); document.write( "500 - μ = -1.28 * 25 \n" ); document.write( "500 - μ = -32 \n" ); document.write( "μ = 500 + 32 \n" ); document.write( "μ = 532\r \n" ); document.write( "\n" ); document.write( "**4. Answer**\r \n" ); document.write( "\n" ); document.write( "The mean should be set to 532 mL.\r \n" ); document.write( "\n" ); document.write( "**Therefore, the mean should be set to 532 mL so that 90% of the bottles contain at least 500 mL.** \n" ); document.write( " \n" ); document.write( " |