document.write( "Question 1170516: The function f defined on (−∞,∞) by
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document.write( "f(x)=22−58x−14(8+29x)7\r
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document.write( "is one-to-one and has range (−∞,∞).
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document.write( "Find f−1(38).\r
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document.write( "Answer :
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document.write( "(Do NOT USE DECIMALS if your answer is a fraction or an irrational number) \n" );
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Algebra.Com's Answer #851159 by CPhill(1959)![]() ![]() You can put this solution on YOUR website! Let $f(x) = 22 - 58x - 14(8+29x)^7$. \n" ); document.write( "We want to find $f^{-1}(38)$. \n" ); document.write( "Let $y = f(x)$. \n" ); document.write( "We want to find $x$ such that $f(x) = 38$. \n" ); document.write( "So we need to solve the equation: \n" ); document.write( "$38 = 22 - 58x - 14(8+29x)^7$. \n" ); document.write( "$38 - 22 = -58x - 14(8+29x)^7$. \n" ); document.write( "$16 = -58x - 14(8+29x)^7$. \n" ); document.write( "$16 + 58x = -14(8+29x)^7$. \n" ); document.write( "$-8 - 29x = 7(8+29x)^7$.\r \n" ); document.write( "\n" ); document.write( "Let $u = 8+29x$. Then $-u = 7u^7$. \n" ); document.write( "$u^7 = -\frac{u}{7}$. \n" ); document.write( "$u^7 + \frac{u}{7} = 0$. \n" ); document.write( "$u(u^6 + \frac{1}{7}) = 0$. \n" ); document.write( "Since $u^6 + \frac{1}{7} > 0$ for all real $u$, we must have $u = 0$. \n" ); document.write( "$8+29x = 0$. \n" ); document.write( "$29x = -8$. \n" ); document.write( "$x = -\frac{8}{29}$.\r \n" ); document.write( "\n" ); document.write( "Now, we verify this value. \n" ); document.write( "$f(-\frac{8}{29}) = 22 - 58(-\frac{8}{29}) - 14(8+29(-\frac{8}{29}))^7$. \n" ); document.write( "$= 22 + 2(8) - 14(8-8)^7$. \n" ); document.write( "$= 22 + 16 - 14(0)^7$. \n" ); document.write( "$= 38 - 0$. \n" ); document.write( "$= 38$.\r \n" ); document.write( "\n" ); document.write( "Thus, $f^{-1}(38) = -\frac{8}{29}$.\r \n" ); document.write( "\n" ); document.write( "Final Answer: The final answer is $\boxed{-8/29}$ \n" ); document.write( " \n" ); document.write( " |