document.write( "Question 1209937: Let f be a function such that
\n" ); document.write( "f(xy) + x = xf(y) + f(x) + xy^2
\n" ); document.write( "for all real numbers x and y. If f(-1) = 3, then compute f(100).
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Algebra.Com's Answer #851141 by ikleyn(52788)\"\" \"About 
You can put this solution on YOUR website!
.
\n" ); document.write( "Let f be a function such that
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\n" ); document.write( "for all real numbers x and y. If f(-1) = 3, then compute f(100).
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\n" ); document.write( "\n" ); document.write( "        Below  I  will show,  in couple of lines,  that the posed  \" problem \" \r
\n" ); document.write( "\n" ); document.write( "        is non-sensical and mathematically  IMPOSSIBLE  self-CONTRADICTORY  gibberish.\r
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\n" ); document.write( "\n" ); document.write( "Indeed,  take   x =1   in this given identity \r
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\n" ); document.write( "\n" ); document.write( "        f(xy) + x = xf(y) + f(x) + xy^2\r
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\n" ); document.write( "\n" ); document.write( "You will get\r
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\n" ); document.write( "\n" ); document.write( "        f(y) + 1 = f(y) + f(1) + y^2.\r
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\n" ); document.write( "\n" ); document.write( "Cancel  f(y)  in both sides and get\r
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\n" ); document.write( "\n" ); document.write( "        1 = f(1) + y^2,\r
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\n" ); document.write( "\n" ); document.write( "or\r
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\n" ); document.write( "\n" ); document.write( "        1 - f(1) = y^2.\r
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\n" ); document.write( "\n" ); document.write( "It says that the function   y --> y^2   has a constant value of   1 - f(1), \r
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\n" ); document.write( "\n" ); document.write( "                which is   I M P O S S I B L E.\r
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\n" ); document.write( "\n" ); document.write( "Therefore,  I call this  \" problem \"  as  GIBBERISH:  such a function,
\n" ); document.write( "as described in the post,  does not exist and can not exist.\r
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\n" ); document.write( "\n" ); document.write( "An immediate consequence from this my post that the  \" solution \"  by  @CPhill in his post is  GIBBERISH,  too.\r
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