document.write( "Question 116767This question is from textbook algerba1
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document.write( ": how many grams of sugar must be added to 60 grams of a solution that is 32% sugar to obtain a solution that is 50% sugar? \n" );
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Algebra.Com's Answer #85114 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! how many grams of sugar must be added to 60 grams of a solution that is 32% sugar to obtain a solution that is 50% sugar? \n" ); document.write( ": \n" ); document.write( "A typical mixture problem, learn this method and you can do most of them easily \n" ); document.write( ": \n" ); document.write( "Let x = amt of pure sugar required, the decimal amt of pure sugar 1.0(x) \n" ); document.write( ": \n" ); document.write( "We know the resulting amt = (x+60) \n" ); document.write( "; \n" ); document.write( "A simple equation: \n" ); document.write( ".32(60) + 1.0(x) = .50(x+60) \n" ); document.write( ": \n" ); document.write( "19.2 + x = .5x + 30 \n" ); document.write( ": \n" ); document.write( "x - .5x = 30 - 19.2 \n" ); document.write( ": \n" ); document.write( ".5x = 10.8 \n" ); document.write( ": \n" ); document.write( "x = 10.8/.5 \n" ); document.write( ": \n" ); document.write( "x = 21.6 grams of pure sugar required \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "We can check our solution by substitution in our original equation: \n" ); document.write( ".32(60) + 21.6 = .5(21.6+60) \n" ); document.write( "19.2 + 21.6 = .5(81.6) \n" ); document.write( " 40.8 = 40.8 \n" ); document.write( " \n" ); document.write( " |