document.write( "Question 116910: Solve the system using substitution or elimination:\r
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document.write( "3x+2y= -12
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document.write( "2x+y= -7
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document.write( "and
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document.write( "2x-4y= -2
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document.write( "4x+8y=0 \n" );
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Algebra.Com's Answer #85112 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! 3X+2Y=-12 NOW MULTIPLY THE OTHER EQUATIOBN BY -2 & ADD THEM \n" ); document.write( "-4X-2Y=14 \n" ); document.write( "-------------------------- \n" ); document.write( "-X=2 \n" ); document.write( "X=-2 ANSWER. \n" ); document.write( "3*-2+2Y=-12 \n" ); document.write( "-6+2Y=-12 \n" ); document.write( "2Y=-12+6 \n" ); document.write( "-2Y=-6 \n" ); document.write( "Y=-6/2 \n" ); document.write( "Y=-3 ANSWER. \n" ); document.write( "PROOF \n" ); document.write( "2*-2-3=-7 \n" ); document.write( "-4-3=-7 \n" ); document.write( "-7=-7 \n" ); document.write( "------------------------------------------- \n" ); document.write( "MULTIPLY THE FIRST EQUATION BY 2 & ADD THEM \n" ); document.write( "4X-8Y=-4 \n" ); document.write( "4X+8Y=0 \n" ); document.write( "---------------- \n" ); document.write( "8X=-4 \n" ); document.write( "X=-4/8 \n" ); document.write( "X=-1/2 ANSWER. \n" ); document.write( "4*1/2+8Y=0 \n" ); document.write( "2+8Y=0 \n" ); document.write( "8Y=-2 \n" ); document.write( "Y=-2/8 \n" ); document.write( "Y=-1/4 ANSWER. \n" ); document.write( "PROOF \n" ); document.write( "2*-1/2-4*-1/4=-2 \n" ); document.write( "-1-1=-2 \n" ); document.write( "-2=-2 \n" ); document.write( " \n" ); document.write( " |