document.write( "Question 1170771: ACT scores have a mean of 21.3 and 8 percent of the scores are above 27. The scores have a distribution that is approximately normal. Find the standard deviation. Round your answer to the nearest tenth \n" ); document.write( "
Algebra.Com's Answer #851101 by CPhill(1959)![]() ![]() You can put this solution on YOUR website! Let's solve this problem step-by-step using the properties of the normal distribution.\r \n" ); document.write( "\n" ); document.write( "**1. Understand the Problem**\r \n" ); document.write( "\n" ); document.write( "* We are given: \n" ); document.write( " * Mean (μ) = 21.3 \n" ); document.write( " * 8% of scores are above 27. \n" ); document.write( " * The distribution is approximately normal. \n" ); document.write( "* We need to find the standard deviation (σ).\r \n" ); document.write( "\n" ); document.write( "**2. Convert Percentage to Z-score**\r \n" ); document.write( "\n" ); document.write( "* If 8% of scores are above 27, then 92% of scores are below 27. \n" ); document.write( "* We need to find the z-score that corresponds to the 92nd percentile (0.92).\r \n" ); document.write( "\n" ); document.write( "* Using a z-table or calculator, we find the z-score that corresponds to 0.92 is approximately 1.41.\r \n" ); document.write( "\n" ); document.write( "**3. Use the Z-score Formula**\r \n" ); document.write( "\n" ); document.write( "* The z-score formula is: \n" ); document.write( " * z = (x - μ) / σ \n" ); document.write( " * Where: \n" ); document.write( " * z is the z-score \n" ); document.write( " * x is the data point (27) \n" ); document.write( " * μ is the mean (21.3) \n" ); document.write( " * σ is the standard deviation (what we want to find)\r \n" ); document.write( "\n" ); document.write( "* Plug in the values: \n" ); document.write( " * 1.41 = (27 - 21.3) / σ\r \n" ); document.write( "\n" ); document.write( "**4. Solve for Standard Deviation (σ)**\r \n" ); document.write( "\n" ); document.write( "* 1.41 = 5.7 / σ \n" ); document.write( "* σ = 5.7 / 1.41 \n" ); document.write( "* σ ≈ 4.04255\r \n" ); document.write( "\n" ); document.write( "**5. Round to the Nearest Tenth**\r \n" ); document.write( "\n" ); document.write( "* σ ≈ 4.0\r \n" ); document.write( "\n" ); document.write( "**Answer**\r \n" ); document.write( "\n" ); document.write( "The standard deviation is approximately 4.0. \n" ); document.write( " \n" ); document.write( " |