document.write( "Question 1170935: #3 3. It is estimated that 4% of people who spend time in the woods will get Lyme disease. For people with Lyme disease, the test to determine if you have it is will give a positive reading 97% of the time. Of people who do not have Lyme disease, the same test will give a negative rating of 92% of the time. Make a tree diagram for this problem and then answer the following questions. Find the probability that A) a person gets a positive reading B) a person gets a negative reading C) a person gets a positive reading and they have Lyme disease D) a person gets a negative reading and they have Lyme disease E ) a person gets a negative reading and they don’t have Lyme diseasePositive \n" ); document.write( "
Algebra.Com's Answer #851042 by CPhill(1959)![]() ![]() You can put this solution on YOUR website! Absolutely! Let's break down this problem step by step.\r \n" ); document.write( "\n" ); document.write( "**1. Tree Diagram**\r \n" ); document.write( "\n" ); document.write( "* **First Branch:** \n" ); document.write( " * Lyme Disease (L): Probability = 0.04 (4%) \n" ); document.write( " * No Lyme Disease (¬L): Probability = 0.96 (96%) \n" ); document.write( "* **Second Branch (for Lyme Disease):** \n" ); document.write( " * Positive Test (+): Probability = 0.97 (97%) \n" ); document.write( " * Negative Test (-): Probability = 0.03 (3%) \n" ); document.write( "* **Second Branch (for No Lyme Disease):** \n" ); document.write( " * Positive Test (+): Probability = 0.08 (8%) (Since negative is 92%) \n" ); document.write( " * Negative Test (-): Probability = 0.92 (92%)\r \n" ); document.write( "\n" ); document.write( "**2. Calculations**\r \n" ); document.write( "\n" ); document.write( "Let's calculate the probabilities of each outcome:\r \n" ); document.write( "\n" ); document.write( "* P(L+) = P(L) * P(+|L) = 0.04 * 0.97 = 0.0388 \n" ); document.write( "* P(L-) = P(L) * P(-|L) = 0.04 * 0.03 = 0.0012 \n" ); document.write( "* P(¬L+) = P(¬L) * P(+|¬L) = 0.96 * 0.08 = 0.0768 \n" ); document.write( "* P(¬L-) = P(¬L) * P(-|¬L) = 0.96 * 0.92 = 0.8832\r \n" ); document.write( "\n" ); document.write( "**3. Answering the Questions**\r \n" ); document.write( "\n" ); document.write( "A) **Probability of a positive reading:**\r \n" ); document.write( "\n" ); document.write( "* P(+) = P(L+) + P(¬L+) = 0.0388 + 0.0768 = 0.1156\r \n" ); document.write( "\n" ); document.write( "B) **Probability of a negative reading:**\r \n" ); document.write( "\n" ); document.write( "* P(-) = P(L-) + P(¬L-) = 0.0012 + 0.8832 = 0.8844\r \n" ); document.write( "\n" ); document.write( "C) **Probability of a positive reading and having Lyme disease:**\r \n" ); document.write( "\n" ); document.write( "* This is P(L+), which we already calculated: 0.0388\r \n" ); document.write( "\n" ); document.write( "D) **Probability of a negative reading and having Lyme disease:**\r \n" ); document.write( "\n" ); document.write( "* This is P(L-), which we already calculated: 0.0012\r \n" ); document.write( "\n" ); document.write( "E) **Probability of a negative reading and not having Lyme disease:**\r \n" ); document.write( "\n" ); document.write( "* This is P(¬L-), which we already calculated: 0.8832\r \n" ); document.write( "\n" ); document.write( "**Summary of Answers**\r \n" ); document.write( "\n" ); document.write( "A) 0.1156 \n" ); document.write( "B) 0.8844 \n" ); document.write( "C) 0.0388 \n" ); document.write( "D) 0.0012 \n" ); document.write( "E) 0.8832 \n" ); document.write( " \n" ); document.write( " |