document.write( "Question 1209904: Simon is one fifth of Danielle's age.\r
\n" ); document.write( "\n" ); document.write( "In 6 Years time, Simon will be one third of Danielle's age.\r
\n" ); document.write( "\n" ); document.write( "How old is Danielle now?
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Algebra.Com's Answer #851024 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "Simon is one-fifth of Danielle's age -- i.e., Danielle is 5 times as old as Simon:

\n" ); document.write( "Let x be Simon's age
\n" ); document.write( "Then Danielle's age is 5x.

\n" ); document.write( "In 6 years, their ages will be x+6 and 5x+6. At that time, Simon will be one-third as old as Danielle -- i.e., she will be 3 times as old as he is:

\n" ); document.write( "\"5x%2B6=3%28x%2B6%29\"
\n" ); document.write( "\"5x%2B6=3x%2B18\"
\n" ); document.write( "\"2x=12\"
\n" ); document.write( "\"x=6\"

\n" ); document.write( "Simon's age is x = 6
\n" ); document.write( "Danielle's age is 5x = 30

\n" ); document.write( "ANSWER: Danielle is 30

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