document.write( "Question 1171064: The average daily expenditure on the food of a middle-income family is P220, with a standard deviation of P15. A sample of 10 families showed the following expenditure: P220, P190, P205, P180, P215, P200, P187, P195, P182, and P201. Test the hypothesis that the average daily expenditure is still 200. Use 0.01 (one-tailed) level. \n" ); document.write( "
Algebra.Com's Answer #850996 by CPhill(1987) You can put this solution on YOUR website! Let's break down this hypothesis test step-by-step.\r \n" ); document.write( "\n" ); document.write( "**1. State the Hypotheses**\r \n" ); document.write( "\n" ); document.write( "* We are testing if the average daily expenditure is still 220, so we will use 220 as our population mean. \n" ); document.write( "* Since the problem does not specify a direction, we will test if the mean is different from 220. This indicates a two-tailed test. \n" ); document.write( "* **Null Hypothesis (H₀):** The average daily expenditure is P220. \n" ); document.write( " * H₀: μ = 220 \n" ); document.write( "* **Alternative Hypothesis (H₁):** The average daily expenditure is not P220. \n" ); document.write( " * H₁: μ ≠ 220 (two-tailed test)\r \n" ); document.write( "\n" ); document.write( "**2. Calculate the Sample Mean and Standard Deviation**\r \n" ); document.write( "\n" ); document.write( "* Sample data: 220, 190, 205, 180, 215, 200, 187, 195, 182, 201 \n" ); document.write( "* Sample size (n) = 10 \n" ); document.write( "* Calculate the sample mean (x̄): \n" ); document.write( " * x̄ = (220 + 190 + 205 + 180 + 215 + 200 + 187 + 195 + 182 + 201) / 10 = 1975 / 10 = 197.5 \n" ); document.write( "* Calculate the sample standard deviation (s): \n" ); document.write( " * First, calculate the squared differences from the mean: \n" ); document.write( " * (220 - 197.5)^2 = 506.25 \n" ); document.write( " * (190 - 197.5)^2 = 56.25 \n" ); document.write( " * (205 - 197.5)^2 = 56.25 \n" ); document.write( " * (180 - 197.5)^2 = 306.25 \n" ); document.write( " * (215 - 197.5)^2 = 306.25 \n" ); document.write( " * (200 - 197.5)^2 = 6.25 \n" ); document.write( " * (187 - 197.5)^2 = 110.25 \n" ); document.write( " * (195 - 197.5)^2 = 6.25 \n" ); document.write( " * (182 - 197.5)^2 = 240.25 \n" ); document.write( " * (201 - 197.5)^2 = 12.25 \n" ); document.write( " * Sum of squared differences = 1606.5 \n" ); document.write( " * Sample variance (s^2) = 1606.5 / (10 - 1) = 1606.5 / 9 = 178.5 \n" ); document.write( " * Sample standard deviation (s) = √178.5 ≈ 13.36\r \n" ); document.write( "\n" ); document.write( "**3. Determine the Test Statistic**\r \n" ); document.write( "\n" ); document.write( "* Since the population standard deviation is unknown and the sample size is small (n < 30), we will use a t-test. \n" ); document.write( "* t = (x̄ - μ) / (s / √n) \n" ); document.write( "* t = (197.5 - 220) / (13.36 / √10) \n" ); document.write( "* t = -22.5 / (13.36 / 3.162) \n" ); document.write( "* t = -22.5 / 4.225 \n" ); document.write( "* t ≈ -5.326\r \n" ); document.write( "\n" ); document.write( "**4. Determine the Critical Value**\r \n" ); document.write( "\n" ); document.write( "* Significance level (α) = 0.01 \n" ); document.write( "* Degrees of freedom (df) = n - 1 = 10 - 1 = 9 \n" ); document.write( "* Type of test: Two-tailed \n" ); document.write( "* Using a t-table or calculator, we find the critical t-values for α = 0.01 and df = 9. \n" ); document.write( "* Critical t-values ≈ ±3.250\r \n" ); document.write( "\n" ); document.write( "**5. Make a Decision**\r \n" ); document.write( "\n" ); document.write( "* Calculated t-statistic: -5.326 \n" ); document.write( "* Critical t-values: ±3.250 \n" ); document.write( "* Since |-5.326| > 3.250, we reject the null hypothesis.\r \n" ); document.write( "\n" ); document.write( "**6. Conclusion**\r \n" ); document.write( "\n" ); document.write( "There is sufficient evidence at the 0.01 significance level to conclude that the average daily expenditure on food is different from P220. \n" ); document.write( " \n" ); document.write( " |