document.write( "Question 1171198: Suppose that historically the average age at which Canadians have been happier than at any other time in their lives is 37 years. A random sample of 50 Canadians taken in 2020 indicated that the mean happiest age was 40 years with a standard deviation equal to 16 years. At the 10 percent level of significance, does this sample indicate that there has been a change in the average age when Canadians are happiest? \r
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\n" ); document.write( "\n" ); document.write( "a) State the null and alternative hypothesis. \r
\n" ); document.write( "\n" ); document.write( "b)State the decision rule\r
\n" ); document.write( "\n" ); document.write( "c)Compute the observed value of the test statistic.\r
\n" ); document.write( "\n" ); document.write( "d) What is your decision regarding the null hypothesis? Don’t forget your concluding statement.\r
\n" ); document.write( "\n" ); document.write( "e) Determine the p-value for this test.
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Algebra.Com's Answer #850978 by CPhill(1987)\"\" \"About 
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Let's break down this hypothesis test step-by-step.\r
\n" ); document.write( "\n" ); document.write( "**a) State the Null and Alternative Hypotheses**\r
\n" ); document.write( "\n" ); document.write( "* **Null Hypothesis (H₀):** The average age at which Canadians are happiest is still 37 years.
\n" ); document.write( " * H₀: μ = 37
\n" ); document.write( "* **Alternative Hypothesis (H₁):** The average age at which Canadians are happiest has changed (is not 37 years).
\n" ); document.write( " * H₁: μ ≠ 37 (two-tailed test)\r
\n" ); document.write( "\n" ); document.write( "**b) State the Decision Rule**\r
\n" ); document.write( "\n" ); document.write( "* Significance level (α) = 10% = 0.10
\n" ); document.write( "* Sample size (n) = 50
\n" ); document.write( "* Since the population standard deviation is unknown and the sample size is large (n > 30), we will use a z-test.
\n" ); document.write( "* For a two-tailed test with α = 0.10, the critical z-values are ±zα/2 = ±z0.05.
\n" ); document.write( "* Using a standard normal distribution table or a calculator, we find that z0.05 ≈ 1.645.
\n" ); document.write( "* **Decision Rule:** Reject H₀ if the absolute value of the calculated z-statistic is greater than 1.645 (|z| > 1.645).\r
\n" ); document.write( "\n" ); document.write( "**c) Compute the Observed Value of the Test Statistic**\r
\n" ); document.write( "\n" ); document.write( "* Sample mean (x̄) = 40 years
\n" ); document.write( "* Population mean (μ) = 37 years
\n" ); document.write( "* Sample standard deviation (s) = 16 years
\n" ); document.write( "* Sample size (n) = 50\r
\n" ); document.write( "\n" ); document.write( "We use the z-statistic formula:\r
\n" ); document.write( "\n" ); document.write( "z = (x̄ - μ) / (s / √n)\r
\n" ); document.write( "\n" ); document.write( "z = (40 - 37) / (16 / √50)\r
\n" ); document.write( "\n" ); document.write( "z = 3 / (16 / 7.071)\r
\n" ); document.write( "\n" ); document.write( "z = 3 / 2.2627\r
\n" ); document.write( "\n" ); document.write( "z ≈ 1.326\r
\n" ); document.write( "\n" ); document.write( "**d) What is your Decision Regarding the Null Hypothesis?**\r
\n" ); document.write( "\n" ); document.write( "* The calculated z-statistic is 1.326.
\n" ); document.write( "* The critical z-values are ±1.645.
\n" ); document.write( "* Since |1.326| < 1.645, we fail to reject the null hypothesis.\r
\n" ); document.write( "\n" ); document.write( "**Concluding Statement:** There is not sufficient evidence at the 10% significance level to conclude that the average age when Canadians are happiest has changed from 37 years.\r
\n" ); document.write( "\n" ); document.write( "**e) Determine the p-value for this Test**\r
\n" ); document.write( "\n" ); document.write( "* The calculated z-statistic is 1.326.
\n" ); document.write( "* Since this is a two-tailed test, we need to find the probability of observing a z-statistic as extreme as 1.326 or -1.326.
\n" ); document.write( "* Using a standard normal distribution table or a calculator, we find the p-value:
\n" ); document.write( " * P(Z > 1.326) ≈ 0.0924
\n" ); document.write( " * P(Z < -1.326) ≈ 0.0924
\n" ); document.write( " * p-value = 2 * 0.0924 ≈ 0.1848\r
\n" ); document.write( "\n" ); document.write( "* Since the p-value (0.1848) is greater than the significance level (0.10), we fail to reject the null hypothesis.
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