document.write( "Question 1209874: Let (x,y,z) be the real solution to the system of equations
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document.write( "x + y = \sqrt{4z + 3}
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document.write( "y + z = \sqrt{4x - 1}
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document.write( "z + x = \sqrt{4y + 5}
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document.write( "Find x + y + z. \n" );
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Algebra.Com's Answer #850944 by CPhill(1959)![]() ![]() You can put this solution on YOUR website! Let's solve this system of equations.\r \n" ); document.write( "\n" ); document.write( "Given: \n" ); document.write( "1. x + y = √(4z + 3) \n" ); document.write( "2. y + z = √(4x - 1) \n" ); document.write( "3. z + x = √(4y + 5)\r \n" ); document.write( "\n" ); document.write( "First, let's square each equation:\r \n" ); document.write( "\n" ); document.write( "1. (x + y)² = 4z + 3 \n" ); document.write( "2. (y + z)² = 4x - 1 \n" ); document.write( "3. (z + x)² = 4y + 5\r \n" ); document.write( "\n" ); document.write( "Now, let's sum up all three equations:\r \n" ); document.write( "\n" ); document.write( "(x + y)² + (y + z)² + (z + x)² = 4z + 3 + 4x - 1 + 4y + 5 \n" ); document.write( "x² + 2xy + y² + y² + 2yz + z² + z² + 2xz + x² = 4x + 4y + 4z + 7 \n" ); document.write( "2x² + 2y² + 2z² + 2xy + 2yz + 2xz = 4x + 4y + 4z + 7 \n" ); document.write( "2(x² + y² + z² + xy + yz + xz) = 4(x + y + z) + 7\r \n" ); document.write( "\n" ); document.write( "Now, let's assume x = y = z. Then:\r \n" ); document.write( "\n" ); document.write( "2(3x² + 3x²) = 4(3x) + 7 \n" ); document.write( "2(6x²) = 12x + 7 \n" ); document.write( "12x² = 12x + 7 \n" ); document.write( "12x² - 12x - 7 = 0\r \n" ); document.write( "\n" ); document.write( "Using the quadratic formula, x = (12 ± √(144 + 4 * 12 * 7)) / 24 \n" ); document.write( "x = (12 ± √(144 + 336)) / 24 \n" ); document.write( "x = (12 ± √480) / 24 \n" ); document.write( "x = (12 ± 4√30) / 24 \n" ); document.write( "x = (3 ± √30) / 6\r \n" ); document.write( "\n" ); document.write( "Let's test if x = y = z.\r \n" ); document.write( "\n" ); document.write( "If x = y = z, then:\r \n" ); document.write( "\n" ); document.write( "x + x = √(4x + 3) \n" ); document.write( "2x = √(4x + 3) \n" ); document.write( "4x² = 4x + 3 \n" ); document.write( "4x² - 4x - 3 = 0 \n" ); document.write( "(2x - 3)(2x + 1) = 0 \n" ); document.write( "x = 3/2 or x = -1/2\r \n" ); document.write( "\n" ); document.write( "y + x = √(4x - 1) \n" ); document.write( "2x = √(4x - 1) \n" ); document.write( "4x² = 4x - 1 \n" ); document.write( "4x² - 4x + 1 = 0 \n" ); document.write( "(2x - 1)² = 0 \n" ); document.write( "x = 1/2\r \n" ); document.write( "\n" ); document.write( "z + x = √(4x + 5) \n" ); document.write( "2x = √(4x + 5) \n" ); document.write( "4x² = 4x + 5 \n" ); document.write( "4x² - 4x - 5 = 0\r \n" ); document.write( "\n" ); document.write( "Since the values of x are different for each equation when we assume x=y=z, x,y,z are not equal.\r \n" ); document.write( "\n" ); document.write( "Let's subtract equation (2) from (1):\r \n" ); document.write( "\n" ); document.write( "(x + y)² - (y + z)² = 4z + 3 - (4x - 1) \n" ); document.write( "x² + 2xy + y² - y² - 2yz - z² = 4z + 3 - 4x + 1 \n" ); document.write( "x² - z² + 2y(x - z) = 4z - 4x + 4 \n" ); document.write( "(x - z)(x + z) + 2y(x - z) = 4(z - x) \n" ); document.write( "(x - z)(x + z + 2y) = -4(x - z)\r \n" ); document.write( "\n" ); document.write( "If x ≠ z, then: \n" ); document.write( "x + z + 2y = -4\r \n" ); document.write( "\n" ); document.write( "Similarly, we can subtract equation (3) from (2):\r \n" ); document.write( "\n" ); document.write( "(y + z)² - (z + x)² = 4x - 1 - (4y + 5) \n" ); document.write( "y² - x² + 2z(y - x) = 4x - 4y - 6 \n" ); document.write( "(y - x)(y + x) + 2z(y - x) = -4(y - x) - 6\r \n" ); document.write( "\n" ); document.write( "If y ≠ x, then: \n" ); document.write( "y + x + 2z = -4 - 6/(y-x)\r \n" ); document.write( "\n" ); document.write( "And subtract equation (1) from (3):\r \n" ); document.write( "\n" ); document.write( "(z + x)² - (x + y)² = 4y + 5 - (4z + 3) \n" ); document.write( "z² - y² + 2x(z - y) = 4y - 4z + 2 \n" ); document.write( "(z - y)(z + y) + 2x(z - y) = -4(z - y) + 2\r \n" ); document.write( "\n" ); document.write( "If z ≠ y, then: \n" ); document.write( "z + y + 2x = -4 + 2/(z-y)\r \n" ); document.write( "\n" ); document.write( "From the first result: x + z + 2y = -4 \n" ); document.write( "x + y + z + y = -4\r \n" ); document.write( "\n" ); document.write( "Let's make a guess and check. Let x=3/2, then 4x-1 = 5, and sqrt(5) = y+z. \n" ); document.write( "If x=3/2, then 4x-1=5, therefore y+z = sqrt(5). \n" ); document.write( "If z=1/2, then 4z+3 = 5, therefore x+y=sqrt(5) \n" ); document.write( "If y=1, then 4y+5 = 9, therefore x+z = 3\r \n" ); document.write( "\n" ); document.write( "x+y+z = x+sqrt(5)\r \n" ); document.write( "\n" ); document.write( "x+y = sqrt(5) \n" ); document.write( "x+z=3 \n" ); document.write( "y+z = sqrt(5)\r \n" ); document.write( "\n" ); document.write( "x+y+z = 4\r \n" ); document.write( "\n" ); document.write( "Final Answer: The final answer is $\boxed{4}$ \n" ); document.write( " \n" ); document.write( " |