document.write( "Question 1171517: For any TFL sentences 𝛼 and 𝛽 that are logically equivalent (i.e., whose truth values agree on every valuation of their sentence letters), does the following entailment hold: \r
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document.write( "𝛽 → 𝛼, 𝛼 ∨ 𝛽 ⊨ 𝛼 ∧ 𝛽\r
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document.write( "Could someone help me with this problem?\r
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document.write( "Thank you!
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Algebra.Com's Answer #850896 by CPhill(1959)![]() ![]() You can put this solution on YOUR website! Let's break down this entailment step-by-step.\r \n" ); document.write( "\n" ); document.write( "**Given:**\r \n" ); document.write( "\n" ); document.write( "* α and β are logically equivalent. This means they have the same truth values under every valuation (interpretation) of their sentence letters.\r \n" ); document.write( "\n" ); document.write( "**Entailment to Prove:**\r \n" ); document.write( "\n" ); document.write( "* β → α, α ∨ β ⊨ α ∧ β\r \n" ); document.write( "\n" ); document.write( "**Analysis:**\r \n" ); document.write( "\n" ); document.write( "1. **Logical Equivalence:** \n" ); document.write( " * Since α and β are logically equivalent, we can say α ≡ β. This means that whenever α is true, β is true, and whenever α is false, β is false.\r \n" ); document.write( "\n" ); document.write( "2. **β → α:** \n" ); document.write( " * Because α ≡ β, the implication β → α is always true. If β is true, α is true, and if β is false, α is false. Thus the implication is always true.\r \n" ); document.write( "\n" ); document.write( "3. **α ∨ β:** \n" ); document.write( " * Since α ≡ β, α ∨ β will be true whenever either α or β (or both) are true. In fact, due to logical equivalence, α ∨ β is true when α is true, and also true when β is true.\r \n" ); document.write( "\n" ); document.write( "4. **α ∧ β:** \n" ); document.write( " * We want to show that α ∧ β is true in all cases where β → α and α ∨ β are true. \n" ); document.write( " * Since β → α is always true, we only need to consider α ∨ β. \n" ); document.write( " * If α ∨ β is true, then at least one of α or β is true. \n" ); document.write( " * Because α ≡ β, if one is true, the other is also true. \n" ); document.write( " * Therefore, both α and β are true. \n" ); document.write( " * Hence, α ∧ β is true.\r \n" ); document.write( "\n" ); document.write( "5. **Entailment:** \n" ); document.write( " * We need to check if in every valuation where β → α and α ∨ β are true, α ∧ β is also true. \n" ); document.write( " * β → α is always true. \n" ); document.write( " * If α ∨ β is true, then both α and β are true (due to logical equivalence). \n" ); document.write( " * Therefore, α ∧ β is true. \n" ); document.write( " * Thus, the entailment holds.\r \n" ); document.write( "\n" ); document.write( "**Conclusion:**\r \n" ); document.write( "\n" ); document.write( "Yes, the entailment β → α, α ∨ β ⊨ α ∧ β holds. \n" ); document.write( " \n" ); document.write( " |