document.write( "Question 1171575: A botanist starts with 3 plants. She takes 5 cuttings from each plant
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document.write( "to start new plants. Later, she takes 5 cuttings from each new plant, and so on.
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document.write( "a) Draw a graph of the number of new plants in each of the first 5 rounds of cuttings.
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document.write( "b) Write an equation to model the number of new plants, P, in the nth round of cuttings.
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document.write( "c) How would the graph and equation change in each scenario? Explain.
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document.write( "i) The botanist starts with 10 plants.
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document.write( "ii) In each round, the botanist takes 2 cuttings from each plant. \n" );
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Algebra.Com's Answer #850894 by CPhill(1959)![]() ![]() You can put this solution on YOUR website! Let's break this down step by step:\r \n" ); document.write( "\n" ); document.write( "**a) Graph of New Plants**\r \n" ); document.write( "\n" ); document.write( "* **Round 1:** \n" ); document.write( " * Starts with 3 plants. \n" ); document.write( " * Takes 5 cuttings from each: 3 plants * 5 cuttings/plant = 15 new plants. \n" ); document.write( "* **Round 2:** \n" ); document.write( " * Starts with 15 plants. \n" ); document.write( " * Takes 5 cuttings from each: 15 plants * 5 cuttings/plant = 75 new plants. \n" ); document.write( "* **Round 3:** \n" ); document.write( " * Starts with 75 plants. \n" ); document.write( " * Takes 5 cuttings from each: 75 plants * 5 cuttings/plant = 375 new plants. \n" ); document.write( "* **Round 4:** \n" ); document.write( " * Starts with 375 plants. \n" ); document.write( " * Takes 5 cuttings from each: 375 * 5 = 1875 \n" ); document.write( "* **Round 5:** \n" ); document.write( " * Starts with 1875 plants. \n" ); document.write( " * Takes 5 cuttings from each: 1875 * 5 = 9375.\r \n" ); document.write( "\n" ); document.write( "Graph:\r \n" ); document.write( "\n" ); document.write( "* X-axis: Round number (1, 2, 3, 4, 5) \n" ); document.write( "* Y-axis: Number of new plants (15, 75, 375, 1875, 9375)\r \n" ); document.write( "\n" ); document.write( "The graph will show an exponential growth curve.\r \n" ); document.write( "\n" ); document.write( "**b) Equation to Model New Plants (P)**\r \n" ); document.write( "\n" ); document.write( "* We see a pattern: \n" ); document.write( " * Round 1: 3 * 5^1 = 15 \n" ); document.write( " * Round 2: 3 * 5^2 = 75 \n" ); document.write( " * Round 3: 3 * 5^3 = 375 \n" ); document.write( " * Round 4: 3*5^4 = 1875 \n" ); document.write( " * Round 5: 3*5^5 = 9375 \n" ); document.write( "* Therefore, the equation is: P = 3 * 5^n, where P is the number of new plants and n is the round number.\r \n" ); document.write( "\n" ); document.write( "**c) Changes in Graph and Equation**\r \n" ); document.write( "\n" ); document.write( "**i) Starting with 10 Plants:**\r \n" ); document.write( "\n" ); document.write( "* **Equation:** \n" ); document.write( " * The initial factor changes from 3 to 10. \n" ); document.write( " * P = 10 * 5^n \n" ); document.write( "* **Graph:** \n" ); document.write( " * The y-intercept (starting point) of the graph will be higher. \n" ); document.write( " * The exponential growth will be steeper, as there are more plants at each round.\r \n" ); document.write( "\n" ); document.write( "**ii) Taking 2 Cuttings from Each Plant:**\r \n" ); document.write( "\n" ); document.write( "* **Equation:** \n" ); document.write( " * The base of the exponent changes from 5 to 2. \n" ); document.write( " * P = 3 * 2^n \n" ); document.write( "* **Graph:** \n" ); document.write( " * The graph will still show exponential growth, but it will be less steep. \n" ); document.write( " * The number of new plants will increase at a slower rate compared to 5 cuttings per plant. \n" ); document.write( " \n" ); document.write( " |