document.write( "Question 1209855: For each of the following functions, determine if the function is increasing, decreasing, even, odd, and/or invertible on its natural domain. Select all the properties that apply.
\n" ); document.write( "f(x) = sqrt{10 - x} + \sqrt{x + 10}
\n" ); document.write( "

Algebra.Com's Answer #850889 by CPhill(1959)\"\" \"About 
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Let's analyze the function f(x) = √(10 - x) + √(x + 10).\r
\n" ); document.write( "\n" ); document.write( "**1. Natural Domain:**\r
\n" ); document.write( "\n" ); document.write( "* **√(10 - x):** 10 - x ≥ 0 => x ≤ 10
\n" ); document.write( "* **√(x + 10):** x + 10 ≥ 0 => x ≥ -10\r
\n" ); document.write( "\n" ); document.write( "Therefore, the domain is the intersection of these two conditions: -10 ≤ x ≤ 10, or [-10, 10].\r
\n" ); document.write( "\n" ); document.write( "**2. Even or Odd:**\r
\n" ); document.write( "\n" ); document.write( "* **Even:** f(-x) = f(x)
\n" ); document.write( "* **Odd:** f(-x) = -f(x)\r
\n" ); document.write( "\n" ); document.write( "Let's test f(-x):\r
\n" ); document.write( "\n" ); document.write( "f(-x) = √(10 - (-x)) + √((-x) + 10)
\n" ); document.write( "f(-x) = √(10 + x) + √(10 - x)\r
\n" ); document.write( "\n" ); document.write( "Comparing:\r
\n" ); document.write( "\n" ); document.write( "* f(-x) = √(10 + x) + √(10 - x)
\n" ); document.write( "* f(x) = √(10 - x) + √(10 + x)\r
\n" ); document.write( "\n" ); document.write( "Therefore, f(-x) = f(x), and the function is **even**.\r
\n" ); document.write( "\n" ); document.write( "Since the function is even, it cannot be odd.\r
\n" ); document.write( "\n" ); document.write( "**3. Increasing or Decreasing:**\r
\n" ); document.write( "\n" ); document.write( "* To determine if the function is increasing or decreasing, we need to analyze its derivative, f'(x).\r
\n" ); document.write( "\n" ); document.write( "f(x) = (10 - x)^(1/2) + (x + 10)^(1/2)\r
\n" ); document.write( "\n" ); document.write( "Now, find the derivative:\r
\n" ); document.write( "\n" ); document.write( "f'(x) = (1/2)(10 - x)^(-1/2)(-1) + (1/2)(x + 10)^(-1/2)(1)
\n" ); document.write( "f'(x) = -1 / (2√(10 - x)) + 1 / (2√(x + 10))\r
\n" ); document.write( "\n" ); document.write( "To find when f'(x) > 0 (increasing) and f'(x) < 0 (decreasing), we need to set f'(x) = 0:\r
\n" ); document.write( "\n" ); document.write( "-1 / (2√(10 - x)) + 1 / (2√(x + 10)) = 0
\n" ); document.write( "1 / (2√(x + 10)) = 1 / (2√(10 - x))
\n" ); document.write( "√(x + 10) = √(10 - x)
\n" ); document.write( "x + 10 = 10 - x
\n" ); document.write( "2x = 0
\n" ); document.write( "x = 0\r
\n" ); document.write( "\n" ); document.write( "Now, let's test intervals:\r
\n" ); document.write( "\n" ); document.write( "* **For -10 ≤ x < 0:**
\n" ); document.write( " * Let's test x = -9:
\n" ); document.write( " * f'(-9) = -1 / (2√(10 - (-9))) + 1 / (2√(-9 + 10))
\n" ); document.write( " * f'(-9) = -1 / (2√19) + 1 / (2√1)
\n" ); document.write( " * f'(-9) ≈ -0.114 + 0.5
\n" ); document.write( " * f'(-9) > 0 (increasing)\r
\n" ); document.write( "\n" ); document.write( "* **For 0 < x ≤ 10:**
\n" ); document.write( " * Let's test x = 9:
\n" ); document.write( " * f'(9) = -1 / (2√(10 - 9)) + 1 / (2√(9 + 10))
\n" ); document.write( " * f'(9) = -1 / (2√1) + 1 / (2√19)
\n" ); document.write( " * f'(9) ≈ -0.5 + 0.114
\n" ); document.write( " * f'(9) < 0 (decreasing)\r
\n" ); document.write( "\n" ); document.write( "Therefore, the function is increasing on [-10, 0] and decreasing on [0, 10].\r
\n" ); document.write( "\n" ); document.write( "**4. Invertibility:**\r
\n" ); document.write( "\n" ); document.write( "* Since the function is not strictly increasing or decreasing over its entire domain, it is **not invertible**.\r
\n" ); document.write( "\n" ); document.write( "**Conclusion:**\r
\n" ); document.write( "\n" ); document.write( "* **Domain:** [-10, 10]
\n" ); document.write( "* **Even**
\n" ); document.write( "* **Invertible:** No
\n" ); document.write( "* **Increasing:** [-10, 0]
\n" ); document.write( "* **Decreasing:** [0, 10]
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