Algebra.Com's Answer #850871 by ikleyn(52943)![\"\"](\"/images/stars/stars-13.gif\")  
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document.write( "At a particular hospital, records show that each day, on average, only 80% of people keep
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document.write( "their appointment at the outpatients’ clinic.
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document.write( "Find the probability that on a day when 200 appointments have been booked;
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document.write( "(b) At least 155 patients keep their appointments [3]
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document.write( "The original problem is a binomial distribution, but since the number of trials is too great,\r\n" );
document.write( "we should use the normal distribution approximation.\r\n" );
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document.write( "It has the mean of m = n*p = 200*0.8 = 160 and the standard deviation \r\n" );
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document.write( " SD =  =  = 5.656854249.\r\n" );
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document.write( "Now you can use your regular calculator like TI-83/84.\r\n" );
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document.write( "Use the standard function normcdf (normal cumulative distribution function) in this format\r\n" );
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document.write( " z1 z2 m SD <<<---=== formatting pattern\r\n" );
document.write( " p = normcdf(154.5, 9999, 160, 5.6568)\r\n" );
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document.write( "Here 154.5 is the continuing approximation to \"at least 155\".\r\n" );
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document.write( " Alternatively, you may use online free of charge calculator\r\n" );
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document.write( " https://onlinestatbook.com/2/calculators/normal_dist.html\r\n" );
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document.write( " which has very convenient visual interface.\r\n" );
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document.write( "The ANSWER is p = 0.8345.\r\n" );
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document.write( "Solved.\r
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