document.write( "Question 1172398: What is the volume of solid in xyz-space bounded by surfaces y = x^2, y = 2 - x^2, z = 0 and z = y + 3? \n" ); document.write( "
Algebra.Com's Answer #850840 by ikleyn(52781)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "What is the volume of solid in xyz-space bounded by surfaces y = x^2, y = 2 - x^2, z = 0 and z = y + 3? \n" ); document.write( "~~~~~~~~~~~~~~~~~~~~~~\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " I will solve this problem mentally.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( "In (x,y)-plane, the area concluded between y = x^2, x-axis, and 0 <= x <= 1 is 1/3.\r\n" ); document.write( "\r\n" ); document.write( "It is elementary calculation from Calculus.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "From it, we deduce, that the area concluded between y = x^2, y = 1 and 0 <= x <= 1 is 2/3.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Hence, the area concluded between y = x^2 and y = 2-x^2 is 4 times 2/3, or 8/3 square units.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Now, our 3D solid consists of two parts.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "One part is a right cylinder 0 <= z <= 3 over its base, which the area concluded \r\n" ); document.write( "between y = x^2 and y = 2-x^2.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "The volume of this cylinder is\r \n" ); document.write( "\n" ); document.write( "Solved mentally.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " My interior voice tells me that this mental solution\r \n" ); document.write( "\n" ); document.write( " is what is expected in this problem.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |