document.write( "Question 1172310: In a design of a highway, a survey for the hill side shows that it is in the following
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\n" ); document.write( "a) Y= 2X-3 ; Y given the value of X BETWEEN -3.5 TO + 5.5 . State the typical standard straight line formula; Draw Straight Line GRAPH for the two formula and Find the steps in the ratio the Y value of the Gradient. \r
\n" ); document.write( "\n" ); document.write( "b) 2Y= 8X-1 ; given the value of X BETWEEN -3.2 TO + 6.3 . State the typical standard straight line formula; Draw Straight Line GRAPH for the formula and Find the steps in the ratio the Y value of the Gradient. \r
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Algebra.Com's Answer #850824 by CPhill(1959)\"\" \"About 
You can put this solution on YOUR website!
Absolutely! Let's break down each part of the problem.\r
\n" ); document.write( "\n" ); document.write( "**a) Y = 2X - 3**\r
\n" ); document.write( "\n" ); document.write( "1. **Standard Straight Line Formula:**
\n" ); document.write( " * The typical standard straight-line formula is y = mx + b, where:
\n" ); document.write( " * m is the slope (gradient) of the line.
\n" ); document.write( " * b is the y-intercept (the value of y when x = 0).
\n" ); document.write( " * In this case, y = 2x - 3, so:
\n" ); document.write( " * m = 2
\n" ); document.write( " * b = -3\r
\n" ); document.write( "\n" ); document.write( "2. **Straight Line Graph:**
\n" ); document.write( " * To draw the graph, you can:
\n" ); document.write( " * Choose a few values of x within the given range (-3.5 to 5.5).
\n" ); document.write( " * Calculate the corresponding y values.
\n" ); document.write( " * Plot the points (x, y) on a coordinate plane.
\n" ); document.write( " * Draw a straight line through the points.
\n" ); document.write( " * Here's how to calculate a couple of points.
\n" ); document.write( " * if x = 0, y = 2(0) - 3 = -3. (0, -3)
\n" ); document.write( " * if x = 1, y = 2(1) - 3 = -1. (1, -1)\r
\n" ); document.write( "\n" ); document.write( "3. **Steps in the Ratio of the Y Value of the Gradient:**
\n" ); document.write( " * The gradient (slope) is 2. This means that for every 1 unit increase in x, y increases by 2 units.
\n" ); document.write( " * The ratio of the change in y to the change in x is 2/1.\r
\n" ); document.write( "\n" ); document.write( "**b) 2Y = 8X - 1**\r
\n" ); document.write( "\n" ); document.write( "1. **Standard Straight Line Formula:**
\n" ); document.write( " * First, we need to rearrange the equation to the standard form (y = mx + b):
\n" ); document.write( " * 2y = 8x - 1
\n" ); document.write( " * y = 4x - 1/2
\n" ); document.write( " * Now, we can identify:
\n" ); document.write( " * m = 4
\n" ); document.write( " * b = -1/2\r
\n" ); document.write( "\n" ); document.write( "2. **Straight Line Graph:**
\n" ); document.write( " * Similar to part a, choose x values within the range (-3.2 to 6.3), calculate y values, and plot the points.
\n" ); document.write( " * Here are a few points.
\n" ); document.write( " * if x = 0, y = 4(0) - 1/2 = -1/2 (0, -0.5)
\n" ); document.write( " * if x = 1, y = 4(1) - 1/2 = 3.5 (1, 3.5)\r
\n" ); document.write( "\n" ); document.write( "3. **Steps in the Ratio of the Y Value of the Gradient:**
\n" ); document.write( " * The gradient (slope) is 4. This means that for every 1 unit increase in x, y increases by 4 units.
\n" ); document.write( " * The ratio of the change in y to the change in x is 4/1.\r
\n" ); document.write( "\n" ); document.write( "**Gradient Comparison**\r
\n" ); document.write( "\n" ); document.write( "* The gradient of the first line (y = 2x - 3) is 2.
\n" ); document.write( "* The gradient of the second line (y = 4x - 1/2) is 4.
\n" ); document.write( "* The second line has a steeper slope than the first line.
\n" ); document.write( "* The second line's gradient is twice that of the first line. (4/2 = 2)
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