document.write( "Question 1172793:  Ten is the average number of oil tankers arriving each day at a certain port city. The facilities at the port can handle at most 10 tankers per day. What is the probability that on a given day\r
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document.write( "(a) Tankers have to be turned away?
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document.write( "(b) Tankers have to be facilitated?
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document.write( "(c) No truck arrived at the port?
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document.write( "(d) Exactly 8 trucks have to be facilitated? \n" );
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| Algebra.Com's Answer #850802 by CPhill(1987)     You can put this solution on YOUR website! Let's solve this problem using the Poisson distribution.\r \n" ); document.write( "\n" ); document.write( "**Given:**\r \n" ); document.write( "\n" ); document.write( "* Average number of tankers arriving per day (λ) = 10 \n" ); document.write( "* Port capacity = 10 tankers per day\r \n" ); document.write( "\n" ); document.write( "**a. Probability Tankers Have to Be Turned Away**\r \n" ); document.write( "\n" ); document.write( "* Tankers are turned away if more than 10 arrive. \n" ); document.write( "* We need to find P(X > 10), where X is the number of tankers arriving. \n" ); document.write( "* P(X > 10) = 1 - P(X ≤ 10) \n" ); document.write( "* We can use the Poisson distribution formula: P(X = k) = (e^(-λ) * λ^k) / k! \n" ); document.write( "* P(X ≤ 10) = Σ [ (e^(-10) * 10^k) / k! ] for k = 0 to 10 \n" ); document.write( "* Using a calculator or statistical software: \n" ); document.write( " * P(X ≤ 10) ≈ 0.5830 \n" ); document.write( "* P(X > 10) = 1 - 0.5830 ≈ 0.4170\r \n" ); document.write( "\n" ); document.write( "**b. Probability Tankers Have to Be Facilitated**\r \n" ); document.write( "\n" ); document.write( "* Tankers are facilitated if 10 or fewer arrive. \n" ); document.write( "* This is P(X ≤ 10). \n" ); document.write( "* From part (a), we already found P(X ≤ 10) ≈ 0.5830\r \n" ); document.write( "\n" ); document.write( "**c. Probability No Truck Arrived at the Port**\r \n" ); document.write( "\n" ); document.write( "* We need to find P(X = 0). \n" ); document.write( "* P(X = 0) = (e^(-10) * 10^0) / 0! \n" ); document.write( "* P(X = 0) = e^(-10) * 1 / 1 \n" ); document.write( "* P(X = 0) ≈ 0.0000454\r \n" ); document.write( "\n" ); document.write( "**d. Probability Exactly 8 Trucks Have to Be Facilitated**\r \n" ); document.write( "\n" ); document.write( "* We need to find P(X = 8). \n" ); document.write( "* P(X = 8) = (e^(-10) * 10^8) / 8! \n" ); document.write( "* P(X = 8) = (e^(-10) * 100000000) / 40320 \n" ); document.write( "* P(X = 8) ≈ 0.1126\r \n" ); document.write( "\n" ); document.write( "**Summary:**\r \n" ); document.write( "\n" ); document.write( "* **(a) Probability tankers have to be turned away:** ≈ 0.4170 \n" ); document.write( "* **(b) Probability tankers have to be facilitated:** ≈ 0.5830 \n" ); document.write( "* **(c) Probability no truck arrived at the port:** ≈ 0.0000454 \n" ); document.write( "* **(d) Probability exactly 8 trucks have to be facilitated:** ≈ 0.1126 \n" ); document.write( " \n" ); document.write( " |