document.write( "Question 1172902: In a class of 50 students 24 like football 21 basketball and cricket six like football and basketball 3 like basketball only, five like all three games, and 14 did not like any of the three games.\r
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document.write( "1.illustrate this information of Venn diagram
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document.write( "2. Find the number of students who like
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document.write( " A. Football and cricket
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document.write( " B. Exactly one of the game
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document.write( " C. Exactly two of the game. \n" );
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Algebra.Com's Answer #850799 by CPhill(1959)![]() ![]() You can put this solution on YOUR website! Absolutely, let's solve this problem step-by-step using a Venn diagram.\r \n" ); document.write( "\n" ); document.write( "**1. Venn Diagram**\r \n" ); document.write( "\n" ); document.write( "Let's use the following notation:\r \n" ); document.write( "\n" ); document.write( "* F = Football \n" ); document.write( "* B = Basketball \n" ); document.write( "* C = Cricket\r \n" ); document.write( "\n" ); document.write( "We are given:\r \n" ); document.write( "\n" ); document.write( "* Total students = 50 \n" ); document.write( "* n(F) = 24 \n" ); document.write( "* n(B) = 21 \n" ); document.write( "* n(F ∩ B) = 6 \n" ); document.write( "* Students who like basketball DISABLED_event_only= 3 \n" ); document.write( "* n(F ∩ B ∩ C) = 5 \n" ); document.write( "* Students who like none of the games = 14\r \n" ); document.write( "\n" ); document.write( "Here's how we'll build the Venn diagram:\r \n" ); document.write( "\n" ); document.write( "1. **Start with the intersection of all three:** \n" ); document.write( " * n(F ∩ B ∩ C) = 5. Place 5 in the center of the Venn diagram where all three circles overlap.\r \n" ); document.write( "\n" ); document.write( "2. **Football and Basketball:** \n" ); document.write( " * n(F ∩ B) = 6. We know 5 like all three, so 6 - 5 = 1 student likes only football and basketball. Place 1 in the F ∩ B region.\r \n" ); document.write( "\n" ); document.write( "3. **Basketball Only:** \n" ); document.write( " * 3 students like only basketball, place a 3 in the B only section of the venn diagram.\r \n" ); document.write( "\n" ); document.write( "4. **Basketball circle:** \n" ); document.write( " * We know n(B)=21. We have 5+1+3=9 of those students accounted for. 21-9=12. We do not yet know how many of those 12 like cricket, so we will fill in the values that we can.\r \n" ); document.write( "\n" ); document.write( "5. **Students who like none:** \n" ); document.write( " * 14 students like none of the games. Place 14 outside the circles.\r \n" ); document.write( "\n" ); document.write( "6. **Total within the circles:** \n" ); document.write( " * 50 total students - 14 who like none = 36 students who like at least one sport.\r \n" ); document.write( "\n" ); document.write( "7. **Football circle:** \n" ); document.write( " * n(F) = 24. We know 5+1=6 of those. 24-6=18. 18 students like football and cricket, or football only. We cannot yet determine the individual values.\r \n" ); document.write( "\n" ); document.write( "8. **Cricket values:** \n" ); document.write( " * We can find the total amount of students that like cricket. 36 students total like at least one sport. 36 - 3 - 1 - 5 - 18 = 9. 9 students like cricket only or cricket and football. We cannot yet determine the individual values.\r \n" ); document.write( "\n" ); document.write( "9. **Completing the diagram:** \n" ); document.write( " * We know that the remaining students that like basketball must total 12. Let x= the students that like basketball and cricket only. 12 = x+5. x=7. 7 students like Basketball and Cricket only. \n" ); document.write( " * We know the students that like cricket total 9+7+5 = 21. \n" ); document.write( " * We know that the football only students equal 24-1-5-students that like football and cricket only. 24-6-cricket and football DISABLED_event_only= football only. 21-5-7=9. 9 students like cricket only. 24-1-5 = 18. 21-9-5-7=0. 18-0=18. 18 students like football only. \n" ); document.write( " * The Venn diagram is complete.\r \n" ); document.write( "\n" ); document.write( "**2. Answers**\r \n" ); document.write( "\n" ); document.write( "**A. Football and Cricket:**\r \n" ); document.write( "\n" ); document.write( "* To find the number of students who like football and cricket, we add the students who like only football and cricket (0) and those who like all three (5): 0+5=5. \n" ); document.write( "* 5 students like football and cricket.\r \n" ); document.write( "\n" ); document.write( "**B. Exactly One Game:**\r \n" ); document.write( "\n" ); document.write( "* Add the number of students who like only football (18), only basketball (3), and only cricket (9): 18 + 3 + 9 = 30. \n" ); document.write( "* 30 students like exactly one game.\r \n" ); document.write( "\n" ); document.write( "**C. Exactly Two Games:**\r \n" ); document.write( "\n" ); document.write( "* Add the number of students who like football and basketball only (1), basketball and cricket only (7), and football and cricket only (0): 1 + 7 + 0 = 8. \n" ); document.write( "* 8 students like exactly two games. \n" ); document.write( " \n" ); document.write( " |