document.write( "Question 1172925: Mrs. Diez has savings account in two banks. The combined amount of these savings is at least Php 150,000. One bank gives an interest of 4% while the other bank gives 6%. In a year, Mrs. Diez receives at most Php12,000.\r
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document.write( "a. What mathematical statements represent the given situation?
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document.write( "b. Draw the graphs of the mathematical statements.
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document.write( "c. How will you determine the amount of savings in each bank account?
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document.write( "d. Give one possible amount of savings in both accounts. \n" );
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Algebra.Com's Answer #850796 by CPhill(1959)![]() ![]() You can put this solution on YOUR website! Absolutely! Let's break down this problem step-by-step.\r \n" ); document.write( "\n" ); document.write( "**a. Mathematical Statements**\r \n" ); document.write( "\n" ); document.write( "Let:\r \n" ); document.write( "\n" ); document.write( "* `x` = amount of savings in the bank with 4% interest \n" ); document.write( "* `y` = amount of savings in the bank with 6% interest\r \n" ); document.write( "\n" ); document.write( "1. **Combined savings:** \n" ); document.write( " * The combined amount of savings is at least Php 150,000. \n" ); document.write( " * Mathematical statement: `x + y ≥ 150000`\r \n" ); document.write( "\n" ); document.write( "2. **Total interest:** \n" ); document.write( " * The total interest received is at most Php 12,000. \n" ); document.write( " * Interest from the 4% bank: 0.04x \n" ); document.write( " * Interest from the 6% bank: 0.06y \n" ); document.write( " * Mathematical statement: `0.04x + 0.06y ≤ 12000`\r \n" ); document.write( "\n" ); document.write( "3. **Non-negative savings:** \n" ); document.write( " * Savings cannot be negative. \n" ); document.write( " * Mathematical statements: `x ≥ 0` and `y ≥ 0`\r \n" ); document.write( "\n" ); document.write( "**b. Graphs of the Mathematical Statements**\r \n" ); document.write( "\n" ); document.write( "1. **x + y ≥ 150000:** \n" ); document.write( " * To graph this, we first graph the line `x + y = 150000`. \n" ); document.write( " * Find the intercepts: \n" ); document.write( " * If x = 0, then y = 150000. (0, 150000) \n" ); document.write( " * If y = 0, then x = 150000. (150000, 0) \n" ); document.write( " * Draw the line connecting these points. \n" ); document.write( " * Since it's `x + y ≥ 150000`, we shade the region above the line.\r \n" ); document.write( "\n" ); document.write( "2. **0.04x + 0.06y ≤ 12000:** \n" ); document.write( " * To make it easier, multiply by 100 to remove decimals: `4x + 6y ≤ 1200000` \n" ); document.write( " * Divide by 2 to simplify: `2x + 3y ≤ 600000` \n" ); document.write( " * Graph the line `2x + 3y = 600000`. \n" ); document.write( " * Find the intercepts: \n" ); document.write( " * If x = 0, then 3y = 600000, so y = 200000. (0, 200000) \n" ); document.write( " * If y = 0, then 2x = 600000, so x = 300000. (300000, 0) \n" ); document.write( " * Draw the line connecting these points. \n" ); document.write( " * Since it's `2x + 3y ≤ 600000`, we shade the region below the line.\r \n" ); document.write( "\n" ); document.write( "3. **x ≥ 0 and y ≥ 0:** \n" ); document.write( " * This means we are only considering the first quadrant of the coordinate plane.\r \n" ); document.write( "\n" ); document.write( "To fully graph this, plot the points and shade the appropriate regions. The solution region is where all shaded areas overlap within the first quadrant.\r \n" ); document.write( "\n" ); document.write( "**c. Determining the Amount of Savings**\r \n" ); document.write( "\n" ); document.write( "1. **Graphing and Intersection:** \n" ); document.write( " * The solution to the system of inequalities is the region where the graphs of all inequalities overlap. \n" ); document.write( " * The corner points of this region are important. They represent possible solutions. \n" ); document.write( " * The exact amounts of savings can be determined by finding the coordinates of the intersection point of the lines `x + y = 150000` and `2x + 3y = 600000`.\r \n" ); document.write( "\n" ); document.write( "2. **Solving the System of Equations:** \n" ); document.write( " * Solve the system of equations: \n" ); document.write( " * `x + y = 150000` \n" ); document.write( " * `2x + 3y = 600000` \n" ); document.write( " * From the first equation, `x = 150000 - y`. \n" ); document.write( " * Substitute this into the second equation: `2(150000 - y) + 3y = 600000` \n" ); document.write( " * `300000 - 2y + 3y = 600000` \n" ); document.write( " * `y = 300000` \n" ); document.write( " * Substitute `y = 300000` back into `x = 150000 - y`: `x = 150000 - 300000 = -150000` \n" ); document.write( " * Because x is negative, this corner point is outside of the feasible region. Therefore the intersection of the two lines is outside of the solution set. We must find another method. \n" ); document.write( " * Test corner points that are created by the intersection of the individual lines, with the x or y axis. \n" ); document.write( " * Test the point (150000,0). \n" ); document.write( " * 150000+0 = 150000. 0.04(150000) + 0.06(0) = 6000. This point is valid. \n" ); document.write( " * Test the point (0,150000). \n" ); document.write( " * 0+150000 = 150000. 0.04(0) + 0.06(150000) = 9000. This point is valid. \n" ); document.write( " * Test the point (300000,0). \n" ); document.write( " * 300000+0 = 300000. 0.04(300000) + 0.06(0) = 12000. This point is valid. \n" ); document.write( " * Test the point (0,200000). \n" ); document.write( " * 0+200000 = 200000. 0.04(0)+0.06(200000) = 12000. This point is valid.\r \n" ); document.write( "\n" ); document.write( "**d. Possible Amounts of Savings**\r \n" ); document.write( "\n" ); document.write( "Here's one possible solution:\r \n" ); document.write( "\n" ); document.write( "* Mrs. Diez could have Php 150,000 in the 4% bank (x = 150000) and Php 0 in the 6% bank (y = 0). \n" ); document.write( " * Total savings: 150000 + 0 = 150000 \n" ); document.write( " * Total interest: (0.04 * 150000) + (0.06 * 0) = 6000\r \n" ); document.write( "\n" ); document.write( "Another possible solution. \n" ); document.write( "* Mrs. Diez could have Php 0 in the 4% bank (x = 0) and Php 150,000 in the 6% bank (y = 150000). \n" ); document.write( " * Total savings: 0 + 150000 = 150000 \n" ); document.write( " * Total interest: (0.04 * 0) + (0.06 * 150000) = 9000.\r \n" ); document.write( "\n" ); document.write( "Another possible solution. \n" ); document.write( "* Mrs. Diez could have Php 300,000 in the 4% bank (x=300000) and Php 0 in the 6% bank (y=0). \n" ); document.write( " * Total savings: 300000+0=300000 \n" ); document.write( " * Total interest: (0.04 * 300000) + (0.06 * 0) = 12000.\r \n" ); document.write( "\n" ); document.write( "Another possible solution. \n" ); document.write( "* Mrs. Diez could have Php 0 in the 4% bank (x=0) and Php 200000 in the 6% bank (y=200000). \n" ); document.write( " * Total savings: 0+200000=200000 \n" ); document.write( " * Total interest: (0.04 * 0) + (0.06 * 200000) = 12000. \n" ); document.write( " \n" ); document.write( " |