document.write( "Question 1173024: Chuck Wells is planning to buy a Winnebago motor home. The listed price is $155,000. Chuck can get a secured add-on interest loan from his bank at 7.45% for as long as 60 months if he pays 15% down. Chuck's goal is to keep his payments below $3,600 per month and amortize the loan in 42 months.\r
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document.write( "Find Chuck's monthly payment (in $) with these conditions. (Round your answer to the nearest cent.)\r
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document.write( "I got the number of payments 60 x 12 = 720
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document.write( "and i did 0.15/12 = 0.0125 for the monthly rate\r
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document.write( "but not sure how to continue from there. \n" );
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Algebra.Com's Answer #850788 by CPhill(1959)![]() ![]() You can put this solution on YOUR website! Here's how to calculate Chuck's monthly payment:\r \n" ); document.write( "\n" ); document.write( "**1. Calculate the Down Payment:**\r \n" ); document.write( "\n" ); document.write( "* Down payment = 15% of $155,000 = $23,250\r \n" ); document.write( "\n" ); document.write( "**2. Calculate the Loan Amount:**\r \n" ); document.write( "\n" ); document.write( "* Loan amount = $155,000 - $23,250 = $131,750\r \n" ); document.write( "\n" ); document.write( "**3. Calculate the Monthly Interest Rate:**\r \n" ); document.write( "\n" ); document.write( "* Monthly interest rate = Annual interest rate / 12 \n" ); document.write( "* Monthly interest rate = 7.45% / 12 = 0.0745 / 12 = 0.00620833 (approximately)\r \n" ); document.write( "\n" ); document.write( "**4. Calculate the Monthly Payment:**\r \n" ); document.write( "\n" ); document.write( "* We'll use the loan payment formula: \n" ); document.write( " * M = P [ i(1 + i)^n ] / [ (1 + i)^n - 1] \n" ); document.write( " * Where: \n" ); document.write( " * M = Monthly payment \n" ); document.write( " * P = Principal loan amount ($131,750) \n" ); document.write( " * i = Monthly interest rate (0.00620833) \n" ); document.write( " * n = Total number of payments (42 months)\r \n" ); document.write( "\n" ); document.write( "* M = $131,750 [ 0.00620833(1 + 0.00620833)^42 ] / [ (1 + 0.00620833)^42 - 1] \n" ); document.write( "* M = $131,750 [ 0.00620833(1.298715) ] / [ 1.298715 - 1] \n" ); document.write( "* M = $131,750 [ 0.0080628 ] / [ 0.298715 ] \n" ); document.write( "* M = $131,750 * 0.026991 \n" ); document.write( "* M = $3556.34 (approximately)\r \n" ); document.write( "\n" ); document.write( "**Therefore, Chuck's monthly payment would be approximately $3,573.30** \n" ); document.write( " \n" ); document.write( " |