document.write( "Question 1174091: Data is collected from 30 male and 20 female employees of SMIU. 50% of the female scored 4 and remaining 2; 30% of the males scored 3, 30% scored 4 and remaining scored 5. Sd of females is 0.8 and that of males is .8. Design hypothesis and test it? \n" ); document.write( "
Algebra.Com's Answer #850708 by CPhill(1987) You can put this solution on YOUR website! Let's break down this problem and design/test a hypothesis.\r \n" ); document.write( "\n" ); document.write( "**1. Data Organization**\r \n" ); document.write( "\n" ); document.write( "* **Females:** \n" ); document.write( " * Total: 20 \n" ); document.write( " * 50% scored 4: 20 * 0.50 = 10 females scored 4. \n" ); document.write( " * 50% scored 2: 20 * 0.50 = 10 females scored 2. \n" ); document.write( " * Female scores: 10 with 4, 10 with 2. \n" ); document.write( " * Sd of females = 0.8 \n" ); document.write( "* **Males:** \n" ); document.write( " * Total: 30 \n" ); document.write( " * 30% scored 3: 30 * 0.30 = 9 males scored 3. \n" ); document.write( " * 30% scored 4: 30 * 0.30 = 9 males scored 4. \n" ); document.write( " * 40% scored 5: 30 * 0.40 = 12 males scored 5. \n" ); document.write( " * Male scores: 9 with 3, 9 with 4, 12 with 5. \n" ); document.write( " * Sd of males = 0.8\r \n" ); document.write( "\n" ); document.write( "**2. Calculate Means**\r \n" ); document.write( "\n" ); document.write( "* **Female Mean (μf):** \n" ); document.write( " * (10 * 4 + 10 * 2) / 20 = (40 + 20) / 20 = 60 / 20 = 3 \n" ); document.write( "* **Male Mean (μm):** \n" ); document.write( " * (9 * 3 + 9 * 4 + 12 * 5) / 30 = (27 + 36 + 60) / 30 = 123 / 30 = 4.1\r \n" ); document.write( "\n" ); document.write( "**3. Hypothesis Design**\r \n" ); document.write( "\n" ); document.write( "* We want to test if there's a significant difference between the mean scores of male and female employees. \n" ); document.write( "* **Null Hypothesis (H0):** There is no significant difference between the mean scores of male and female employees. (μm = μf) \n" ); document.write( "* **Alternative Hypothesis (H1):** There is a significant difference between the mean scores of male and female employees. (μm ≠ μf) \n" ); document.write( "* This is a two-tailed test.\r \n" ); document.write( "\n" ); document.write( "**4. Test Statistic**\r \n" ); document.write( "\n" ); document.write( "* We'll use a two-sample t-test because we're comparing two means. Since we have the standard deviation of the populations we can use a z test. \n" ); document.write( "* We will use the following formula. \n" ); document.write( " * z = (μm - μf) / sqrt((σm^2/nm) + (σf^2/nf)) \n" ); document.write( " * Where: \n" ); document.write( " * μm = 4.1 (male mean) \n" ); document.write( " * μf = 3 (female mean) \n" ); document.write( " * σm = 0.8 (male standard deviation) \n" ); document.write( " * σf = 0.8 (female standard deviation) \n" ); document.write( " * nm = 30 (number of males) \n" ); document.write( " * nf = 20 (number of females)\r \n" ); document.write( "\n" ); document.write( "**5. Calculation**\r \n" ); document.write( "\n" ); document.write( "* z = (4.1 - 3) / sqrt((0.8^2/30) + (0.8^2/20)) \n" ); document.write( "* z = 1.1 / sqrt((0.64/30) + (0.64/20)) \n" ); document.write( "* z = 1.1 / sqrt(0.02133 + 0.032) \n" ); document.write( "* z = 1.1 / sqrt(0.05333) \n" ); document.write( "* z = 1.1 / 0.2309 \n" ); document.write( "* z ≈ 4.76\r \n" ); document.write( "\n" ); document.write( "**6. Determine the Critical Value and Make a Decision**\r \n" ); document.write( "\n" ); document.write( "* Let's use a significance level (alpha) of 0.05. \n" ); document.write( "* For a two-tailed test at alpha = 0.05, the critical z-values are ±1.96. \n" ); document.write( "* Our calculated z-value (4.76) is far outside this range. \n" ); document.write( "* Therefore, we reject the null hypothesis.\r \n" ); document.write( "\n" ); document.write( "**7. Conclusion**\r \n" ); document.write( "\n" ); document.write( "* There is a statistically significant difference between the mean scores of male and female employees at SMIU. \n" ); document.write( "* The male employees, on average, scored higher than the female employees. \n" ); document.write( " \n" ); document.write( " |