document.write( "Question 1174399: The Dean of a college wants to use the proportion of a population to determine the sample size needed to interview regarding their thoughts about the new school structures.She want to be able to assert with a probability 0.95 that her error will be at most 0.05. Similar pols in the past showed that 65% approved the new structure. How large a sample does the Dean need?
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Algebra.Com's Answer #850669 by CPhill(2189) You can put this solution on YOUR website! **1. Identify the Parameters:**\r \n" ); document.write( "\n" ); document.write( "* Confidence Level: 95% (This gives us a z-score of 1.96) \n" ); document.write( "* Margin of Error (E): 0.05 \n" ); document.write( "* Estimated Population Proportion (p̂): 0.65 (from past polls) \n" ); document.write( "* Estimated Population Proportion who don't approve (q̂) = 1 - p̂ = 0.35\r \n" ); document.write( "\n" ); document.write( "**2. Use the Sample Size Formula:**\r \n" ); document.write( "\n" ); document.write( "The formula for calculating the sample size (n) for estimating a population proportion is:\r \n" ); document.write( "\n" ); document.write( "n = (z^2 * p̂ * q̂) / E^2\r \n" ); document.write( "\n" ); document.write( "**3. Plug in the Values:**\r \n" ); document.write( "\n" ); document.write( "n = (1.96^2 * 0.65 * 0.35) / 0.05^2\r \n" ); document.write( "\n" ); document.write( "**4. Calculate:**\r \n" ); document.write( "\n" ); document.write( "n ≈ 350.28\r \n" ); document.write( "\n" ); document.write( "**5. Round Up:**\r \n" ); document.write( "\n" ); document.write( "Since we cannot have a fraction of a person, always round the sample size up to the nearest whole number.\r \n" ); document.write( "\n" ); document.write( "n = 351\r \n" ); document.write( "\n" ); document.write( "**Therefore, the Dean needs a sample size of 351 students to achieve the desired level of confidence and margin of error.** \n" ); document.write( " |