document.write( "Question 1209803: Let
\n" ); document.write( "a + ar + ar^2 + ar^3 + \dotsb
\n" ); document.write( "be an infinite geometric series. The sum of the series is 9. The sum of the cubes of all the terms is 36. Find the common ratio.
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Algebra.Com's Answer #850647 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "\"a%2Bar%2Bar%5E2\"+...

\n" ); document.write( "That sum is 9

\n" ); document.write( "[1] \"a%2F%281-r%29=9\"

\n" ); document.write( "\"a%5E3%2Ba%5E3r%5E3%2Ba%5E3r%5E6\"+...

\n" ); document.write( "That sum is 36

\n" ); document.write( "[2] \"a%5E3%2F%281-r%5E3%29=36\"

\n" ); document.write( "From [1],

\n" ); document.write( "[3] \"a%5E3=729%281-r%29%5E3\"

\n" ); document.write( "From [2],

\n" ); document.write( "[4] \"a%5E3=36%281-r%5E3%29\"

\n" ); document.write( "Equating [3] and [4]...

\n" ); document.write( "\"729%281-r%29%5E3=36%281-r%5E3%29\"
\n" ); document.write( "\"%281-r%5E3%29%2F%281-r%29%5E3=729%2F36=81%2F4\"

\n" ); document.write( "Simplify using \"1-r%5E3=%281-r%29%281%2Br%2Br%5E2%29\"

\n" ); document.write( "\"%28%281-r%29%281%2Br%2Br%5E2%29%29%2F%281-r%29%5E3=81%2F4\"
\n" ); document.write( "\"%281%2Br%2Br%5E2%29%2F%281-r%29%5E2=81%2F4\"
\n" ); document.write( "\"81%281-2r%2Br%5E2%29=4%281%2Br%2Br%5E2%29\"
\n" ); document.write( "\"81-162r%2B81r%5E2=4%2B4r%2B4r%5E2\"
\n" ); document.write( "\"77r%5E2-166r%2B77=0\"

\n" ); document.write( "Use the quadratic formula to solve; choose the value of r that is less than 1, since both series converge.

\n" ); document.write( "\"r=%28166-sqrt%28166%5E2-4%2877%29%2877%29%29%29%2F154\"

\n" ); document.write( "ANSWER: r = 0.6755342 to several decimal places

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