document.write( "Question 1176438: 3. A principal states that in his school, the average number of days per year missed by a student due to illness is less than 10. The ff. data show the number of days missed by 40 students a year. Is there sufficient evidence to believe the principal’s claim at alpha=.05? \n" ); document.write( "
Algebra.Com's Answer #850578 by CPhill(1987)![]() ![]() You can put this solution on YOUR website! To test the principal's claim, we'll perform a one-tailed t-test. Since you haven't provided the actual data, I'll outline the steps and provide a general solution. You'll need to plug in the data to complete the calculations.\r \n" ); document.write( "\n" ); document.write( "**1. State the Hypotheses:**\r \n" ); document.write( "\n" ); document.write( "* **Null Hypothesis (H0):** μ ≥ 10 (The average number of days missed is greater than or equal to 10) \n" ); document.write( "* **Alternative Hypothesis (H1):** μ < 10 (The average number of days missed is less than 10)\r \n" ); document.write( "\n" ); document.write( "**2. Determine the Significance Level:**\r \n" ); document.write( "\n" ); document.write( "* α = 0.05\r \n" ); document.write( "\n" ); document.write( "**3. Calculate the Sample Statistics:**\r \n" ); document.write( "\n" ); document.write( "* **Sample Size (n):** 40 \n" ); document.write( "* **Calculate the Sample Mean (x̄):** Sum all the data points and divide by 40. \n" ); document.write( "* **Calculate the Sample Standard Deviation (s):** Use the formula: \n" ); document.write( " * s = √[Σ(xᵢ - x̄)² / (n - 1)]\r \n" ); document.write( "\n" ); document.write( "**4. Calculate the Test Statistic (t):**\r \n" ); document.write( "\n" ); document.write( "* t = (x̄ - μ) / (s / √n) \n" ); document.write( " * Where: \n" ); document.write( " * x̄ = sample mean \n" ); document.write( " * μ = population mean (10) \n" ); document.write( " * s = sample standard deviation \n" ); document.write( " * n = sample size\r \n" ); document.write( "\n" ); document.write( "**5. Determine the Critical Value:**\r \n" ); document.write( "\n" ); document.write( "* Since we are performing a left-tailed test at α = 0.05 with df = n - 1 = 39, we need to find the critical t-value from the t-distribution table. \n" ); document.write( "* For df = 39 and α = 0.05 (one-tailed), the critical t-value is approximately -1.684.\r \n" ); document.write( "\n" ); document.write( "**6. Make a Decision:**\r \n" ); document.write( "\n" ); document.write( "* **If the calculated t-statistic is less than the critical t-value (-1.684), reject the null hypothesis.** This means there is sufficient evidence to support the principal's claim. \n" ); document.write( "* **If the calculated t-statistic is greater than or equal to the critical t-value, fail to reject the null hypothesis.** This means there is not sufficient evidence to support the principal's claim.\r \n" ); document.write( "\n" ); document.write( "**Example (Illustrative - You need to plug in your data):**\r \n" ); document.write( "\n" ); document.write( "Let's say, after calculating from your data, you find:\r \n" ); document.write( "\n" ); document.write( "* x̄ = 8.5 \n" ); document.write( "* s = 4.0\r \n" ); document.write( "\n" ); document.write( "Then:\r \n" ); document.write( "\n" ); document.write( "* t = (8.5 - 10) / (4.0 / √40) \n" ); document.write( "* t = -1.5 / (4.0 / 6.3245) \n" ); document.write( "* t = -1.5 / 0.63245 \n" ); document.write( "* t = -2.372\r \n" ); document.write( "\n" ); document.write( "In this example:\r \n" ); document.write( "\n" ); document.write( "* -2.372 < -1.684\r \n" ); document.write( "\n" ); document.write( "Therefore, you would reject the null hypothesis.\r \n" ); document.write( "\n" ); document.write( "**Conclusion:**\r \n" ); document.write( "\n" ); document.write( "* **If your calculated t-statistic is less than -1.684, there is sufficient evidence to support the principal's claim that the average number of days missed is less than 10 at α = 0.05.** \n" ); document.write( "* **If your calculated t-statistic is greater than or equal to -1.684, there is not sufficient evidence to support the principal's claim at α = 0.05.** \n" ); document.write( " |