document.write( "Question 1176997: ~F → G I - F v G
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Algebra.Com's Answer #850541 by CPhill(1959)![]() ![]() You can put this solution on YOUR website! Let's break down this logical expression and determine the relationship between `~F → G` and `F v G`.\r \n" ); document.write( "\n" ); document.write( "**Understanding the Symbols**\r \n" ); document.write( "\n" ); document.write( "* `~`: Negation (NOT) \n" ); document.write( "* `→`: Implication (IF...THEN) \n" ); document.write( "* `v`: Disjunction (OR)\r \n" ); document.write( "\n" ); document.write( "**Breaking Down the Expressions**\r \n" ); document.write( "\n" ); document.write( "1. **`~F → G`** (NOT F implies G) \n" ); document.write( " * This statement is true in all cases except when `~F` is true and `G` is false. \n" ); document.write( " * In other words, it's false only when `F` is false and `G` is false.\r \n" ); document.write( "\n" ); document.write( "2. **`F v G`** (F OR G) \n" ); document.write( " * This statement is true when either `F` is true, `G` is true, or both are true. \n" ); document.write( " * It is only false when both `F` and `G` are false.\r \n" ); document.write( "\n" ); document.write( "**Truth Table**\r \n" ); document.write( "\n" ); document.write( "To see the relationship clearly, let's create a truth table:\r \n" ); document.write( "\n" ); document.write( "| F | G | ~F | ~F → G | F v G | \n" ); document.write( "| :---- | :---- | :---- | :----- | :---- | \n" ); document.write( "| True | True | False | True | True | \n" ); document.write( "| True | False | False | True | True | \n" ); document.write( "| False | True | True | True | True | \n" ); document.write( "| False | False | True | False | False |\r \n" ); document.write( "\n" ); document.write( "**Analysis**\r \n" ); document.write( "\n" ); document.write( "* Notice that the truth values for `~F → G` and `F v G` are identical in all rows of the truth table.\r \n" ); document.write( "\n" ); document.write( "**Conclusion**\r \n" ); document.write( "\n" ); document.write( "Therefore, `~F → G` is logically equivalent to `F v G`. They have the same truth values under all possible combinations of `F` and `G`. \n" ); document.write( " \n" ); document.write( " |