document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=116870>Question 116870</A>: <I><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "A cabin cruiser travels 20 miles in the same time that a power boat travels 40 miles.  The cruiser travels 5 mph slower than the power boat.  Find the speed of each boat. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #85054 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=85054\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> SEEING AS THE TIMES ARE EQUAL THEN D/(R-5) FOR THE CRUISE=D/R FOR THE POWER BOAT:<BR>\n" );
document.write( "20/(R-5)=40/R CROSS MULTPLY<BR>\n" );
document.write( "40(R-5)=20R<BR>\n" );
document.write( "40R-200=20R<BR>\n" );
document.write( "40R-20R=200<BR>\n" );
document.write( "20R=200<BR>\n" );
document.write( "R=200/20<BR>\n" );
document.write( "R=10 MPH FOR THE POWER BOAT.<BR>\n" );
document.write( "10-5=5 MPH FOR THE CRUISER.<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "20/5=40/10<BR>\n" );
document.write( "4=4<BR>\n" );
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